Question

A rectangle's length is 3.5 feet longer than its width. The perimeter of the rectangle is 58 feet. The width, w, can be found using the equation below.
2w+2(w+3.5)=58

Answer 1

For this case we have to:

w: Represents the width of the rectangle

L: Represents the length of the rectangle

Then, the perimeter is given by:

$P = 2w+2L$

According to the statement we have:

$L = 3.5+w\\P = 58$

Substituting we obtain the given equation:

$2w+2 (3.5 +w) = 58\\2w+7+2w = 58\\4w+7 = 58\\4w = 58-7\\4w = 51\\w = \frac {51} {4}\\w = 12.75$

Thus, the width of the rectangle is 12.75 feet

Answer:

The width of the rectangle is 12.75 feet