Given:
The three exterior angles of a pentagon measures 60,80 and 90.
To find:
The measure of other two exterior angle, assuming them equally.
Solution:
Let x be the measure of two other exterior angles of the pentagon.
We know that the sum of all exterior angles of a pentagon is 360 degrees.
Divide both sides by 2.
Therefore, the measures of both exterior angles are 65 degrees.
Answer:
16
Step-by-step explanation:
24/8=3
48/3=16
Answer:
Area of rectangle: 256
Area of triangle 1: 24
Area of triangle 2: 16
Area of triangle 3: 96
Area of trapezoid: 120
Step-by-step explanation:
I just did the question on the thing so Ik I'm right.
-The graph measures by twos. To get the area of the rectangle get the base times height of it. That would be 16x16=256.
-Get base (8) times height (6) of triangle 1 then divide by 2, remember to count the squares by 2 for finding all areas. The formula would be 1/2(b)(h) because dividing by 2 is the same as multiplying times 1/2. Plug it in and (8)(6)=48 then divide by 2 which equals 24.
-Same formula for triangle 2. Plug it in and (8)(4)=32 and divide by 2 and it equals 16.
-Same formula for triangle 3. Plugged in is (12)(16)=192 divide by 2 and it equals 96.
-To find the area of the trapezoid get your rectangle area (256) and subtract all the triangle areas. So 256 - 6 - 16 - 96 = 120.
Answer:
Vertex (2,2)
y- Intercept is 10
On problems like this, use Desmos Graphing. It helps a lot.
The right answer for the question that is being asked and shown above is that: "180 - line." Tanisha cut a triangle with angles of 62°, 30°, and 88° in three pieces so that each piece had one angle of the triangle.She arranged the three angles <span>connected together such that the three corners of the triangle were all touching.</span><span> </span>
