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torisob [31]
3 years ago
11

In a class of 25 students, 15 of them have a cat, 16 of them have a dog and 3 of them have neither.

Mathematics
1 answer:
den301095 [7]3 years ago
5 0

Answer

the probility is 9

Step-by-step explanation:

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Use the information below to answer the following questions.
Anestetic [448]
I got the same exact question from someone else couple min earlier. Here you go:)

4 0
3 years ago
What is the equation, in slope-intercept form, of the line that is perpendicular to the line
wolverine [178]

Answer:

y=3/2x+1

Step-by-step explanation:

y-4= -⅔(x-6)

y-4=-⅔x+4

y=-⅔x+4+4

(equation of line 1) y= -⅔x+8 gradient= -⅔

(line 2)gradient=3/2

note* the gradients of perpendicular lines multiplied result to -1

gradient=<u>y²-y²</u>

<u> </u><u> </u><u> </u><u> </u><u> </u><u> </u><u> </u><u> </u><u> </u><u> </u><u> </u><u> </u><u> </u><u> </u><u> </u><u> </u>x²-x¹

<u>3</u><u> </u>=<u>y</u><u>+</u><u>2</u>

<u> </u><u> </u>2. x+2

multiply both sides by 2(x+2)to remove the denominators

3(x+2)=2(y+2)

3x+6=2y+4

3x+6-4=2y

3x+2=2y

divide all sides by 2

3/2x+1=y

y=3/2x+1

8 0
3 years ago
The percentage of cotton in material used to manufacture men's shirts follows.
velikii [3]

Answer:

Median = 34.55

Quartiles:

Q1 = 33.1

Q2 = 34.55

Q3 = 35.6

Inter Quartile range = 2.5

Step-by-step explanation:

Step 1

We arrange the given the following data from lowest to the highest

32.0, 32.1, 32.1, 32.2, 32.4, 32.5, 32.5, 32.5, 32.8, 32.8, 32.8, 32.8, 32.9, 32.9, 33.0, 33.0, 33.2, 33.2, 33.2, 33.2, 33.5, 33.6, 33.8, 33.8, 33.9, 34.0, 34.0, 34.1, 34.1, 34.3, 34.4, 34.5, 34.6, 34.6, 34.6, 34.7, 34.7, 35.0, 35.0, 35.1, 35.1, 35.2, 35.4, 35.5, 35.5, 35.5, 35.5, 35.6, 35.6, 36.1, 36.3, 36.4, 36.4, 36.4, 36.5, 36.6, 36.7, 36.7, 37.0, 37.1, 37.4, 37.4, 37.6, 37.8

a. Construct a stem-and-leaf display for the data.

Stem and leaf Display

Stem | Leaf

32 | 0,1,1,2,4,5,5,5,8,8,8,8,9,9

33 | 0,0,2,2,2,2,5,6,8,8,9

34 | 0,0,1,1,3,4,5,6,6,6,7,7

35 | 0,0,1,1,2,4,5,5,5,5,6,6,

36 | 1,3,4,4,4,5,6,7,7,

37 | 0,1,4,4,6,8

b. Calculate the median and quartiles of these data.

Number of terms = 64

1) Median = 1/2(n + 1)th value

n = 64

= 1/2(64 + 1)th

= 1/2(65)th

= 32.5 th value

This means it is between the 32nd and 33rd value

32nd = 34.5

33rd = 34.6

= 34.5 + 34.6/2

= 69.1/2

= 34.55

2) First Quartile

1/4(n + 1)th value

n = 64

= 1/4(64 + 1)th

= 1/4(65)th

= 16.5th value

This means it is between the 16th and 17th value

16th value = 33.0

17tj value = 33.2

= 33.0 + 33.2/2

= 66.2/2

= 34.55

Q1 --> 33.1

3)Second Quartile = Median

1/2(n + 1)th value

n = 64

= 1/2(64 + 1)th

= 1/2(65)th

= 32.5 th value

This means it is between the 32nd and 33rd value

32nd = 34.5

33rd = 34.6

= 34.5 + 34.6/2

= 69.1/2

= 34.55

Q2 --> 34.55

Third Quartile

3/4(n + 1)th value

n = 64

= 3/4(64 + 1)th

= 3/4(65)th

= 48.75 th value

This means it is towards the 49th value

32nd = 34.5

Hence,

Q3 --> 35.6

Inter Quartile range

Q3 - Q1

= 35.6 - 33.1

= 2.5

8 0
3 years ago
Find the perimeter of the composite figure.
iVinArrow [24]

Answer:

87.92

Step-by-step explanation:

you have to multiply 3.14 by 2 which will give you 6.28, then you multiply 6.28 by 14 which gives you 87.92. hope this helps

4 0
3 years ago
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