Answer:
{f|0 ≤ f(x)}; x² - 4x + 5
Step-by-step explanation:
To find the Quadratic Equation, plug the <em>vertex</em> into the Vertex Equation FIRST, <em>y = </em><em>a</em><em>(</em><em>x</em><em> </em><em>-</em><em> </em><em>h</em><em>)</em><em>²</em><em> </em><em>+</em><em> </em><em>k</em>, where (<em>h</em><em>,</em><em> </em><em>k</em>) → (<em>2,</em><em> </em><em>1</em>)<em> </em>is the vertex, plus, -h gives you the OPPOSITE terms of what they really are, and k gives you the EXACT terms of what they really are: (x - 2)² + 1. Doing this will give you the Quadratic Equation of <em>x² - 4x + 5</em>. You understand now?
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Answer:
9
Step-by-step explanation:
The answer is 64 because it goes by 2 abd it needs to find the line between the boxes
Answer:
P=3
Step-by-step explanation:
Step 1: Simplify both sides of the equation.
−2=5p+3p−8−6p
−2=5p+3p+−8+−6p
−2=(5p+3p+−6p)+(−8)(Combine Like Terms)
−2=2p+−8
−2=2p−8
Step 2: Flip the equation.
2p−8=−2
Step 3: Add 8 to both sides.
2p−8+8=−2+8
2p=6
Step 4: Divide both sides by 2.
2p2=62
p=3
Answer: 64
Step-by-step explanation:
If EFGH is a parallelogram, its diagonals bisect each other meaning EJ and JG are congruent.
EJ = JG
4w + 4 = 2w + 18
Subtract 2w from both sides
2w + 4 = 18
Subtract 4 from both sides
2w = 14
Divide both sides by 2
w = 7
EG = EJ + JG
EG = 4w + 4 + 2w + 18
EG = 6w + 22
Now that we know what 'w' is, we can substitute it for 7
EG = 6 (7) + 22
EG = 42 + 22 = 64
The measure of EG is 64.
Hope that helped!
