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dolphi86 [110]
3 years ago
13

What are 2 equivalent fractions for 4/5?

Mathematics
1 answer:
VashaNatasha [74]3 years ago
8 0
Two equivalent fractions would be 8/10
and 12/15<span />
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A reasonable estimate for the mass of a baby would be 7 __ pounds
zaharov [31]
Maybe 7.4 pounds idk sorry if I’m wrong
7 0
2 years ago
Read 2 more answers
given y&gt;0 and dy/dx=(3x^2+4x)/yif the point (1,√10) is on the graph relating x and y, then what is y when x=0
jonny [76]
\dfrac{\mathrm dy}{\mathrm dx}=\dfrac{3x^2+4x}y\iff y\,\mathrm dy=(3x^2+4x)\,\mathrm dx
\implies\displaystyle\int y\,\mathrm dy=\int(3x^2+4x)\,\mathrm dx
\implies \dfrac12y^2=x^3+2x^2+C

When x=1 you have y=\sqrt{10}, so

\dfrac12(\sqrt{10})^2=1^3+2(1)^2+C\implies 5=1+2+C\implies C=2

and so the particular solution to the ODE is

\dfrac12y^2=x^3+2x^2+2

Then when x=0, you get

\dfrac12y^2=0^3+2(0)^2+2=2
\implies y^2=4
\implies y=2

where we omitted the negative root because it's given that y>0.
4 0
3 years ago
What is the probability that a point chosen at random in the given figure will be inside the smaller square?
Aliun [14]
I have to interpret that:

1) the smaller square has side length = 3 cm

2) the bigger square has side length = 5 cm

3) the smaller square is completely inside the bigger square.

4) the points cannot be outside the bigger square



Under those assumptions the probability that a point is inside the smaller square  is

P (inside the smaller square) = area of the smaller square / area of the bigger square

P (inside the smaller squere) = (3cm)^2 / (5cm)^2 =  9 / 25


Answer: 9 / 25
8 0
3 years ago
Which one of the following solids can produce this two-dimensional shape when sliced vertically?
Oksana_A [137]

Answer:

option 2

Step-by-step explanation:

3 0
2 years ago
Read 2 more answers
1) After a dilation, (-60, 15) is the image of (-12, 3). What are the coordinates of the image of (-2,-7) after the same dilatio
BARSIC [14]

Answer:

a) k = 5; (-10, -35)

Step-by-step explanation:

Given:

Co-ordinates:

Pre-Image = (-12,3)

After dilation

Image = (-60,15)

The dilation about the origin can be given as :

Pre-Image(x,y)\rightarrow Image(kx,ky)

where k represents the scalar factor.

We can find value of k for the given co-ordinates by finding the ratio of x or y co-ordinates of the image and pre-image.

k=\frac{Image}{Pre-Image}

For the given co-ordinates.

Pre-Image = (-12,3)

Image = (-60,15)

The value of k=\frac{-60}{-12}=5

or k=\frac{15}{3}=5

As we get k=5 for both ratios i.e of x and  y co-ordinates, so we can say the image has been dilated by a factor of 5 about the origin.

To find the image of (-2,-7), after same dilation, we will multiply the co-ordinates with the scalar factor.

Pre-Image(-2,-7)\rightarrow Image((-2\times5),(-7\times 5))

Pre-Image(-2,-7)\rightarrow Image(-10,-35) (Answer)

7 0
2 years ago
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