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3 years ago

Q.4 a) If a= x+y and b= x-y , show that I) (a+b)²= 4x² ii) ( a-b)²= 4y²

Mathematics

1 answer:

olasank [31]3 years ago

3 0

Answer:

Below.

Step-by-step explanation:

i) (a + b)^2 = a^2 + 2ab + b^2

= (x + y)^2 + 2(x + y)(x - y) + (x - y)^2

= x^2 + 2xy + y^2 + 2(x^2 - y^2) + x^2 - 2xy + y^2

= x^2 + 2x^2 + x^2 + y^2 - 2y^2 + y^2 + 2xy - 2xy

= 4x^2.

ii) (a - b)^2 = a^2 + b^2 - 2ab

= (x + y)^2 + (x - y)^2 - 2 - 2(x^2 - y^2)

= x^2 + 2xy + y^2 + x^2 - 2xy + y^2 - 2x^2 + 2y^2

= x^2 + x^2 - 2x^2 + y^2 + y^2 + 2y^2 + 2xy - 2xy

= 4y^2.

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2 years ago

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2 years ago

What property is -3(m+8)=-3m-24

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Answer:

All real numbers are solutions.

Step-by-step explanation:

Step 1: Simplify both sides of the equation.

−3(m+8)=−3m−24

(−3)(m)+(−3)(8)=−3m+−24(Distribute)

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Step 2: Add 3m to both sides.

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2 years ago

Q.4 a) If a= x+y and b= x-y , show that I) (a+b)²= 4x² ii) ( a-b)²= 4y²​

Q.4 a) If a= x+y and b= x-y , show that I) (a+b)²= 4x² ii) ( a-b)²= 4y²