10 students per gender:
Boys: <span>four Xs over five and one X over zero, two, three, four, ten, and twelve.
5, 5, 5, 5, 0, 2, 3, 4, 10, 12 </span>→ 0, 2, 3, 4, 5, 5, 5, 5, 10, 12<span>
mean: 5.1
range: 12
</span><span>Girls: three Xs above eight, two Xs above three and four, and one X above two, six and seven.
8, 8, 8, 3, 3, 4, 4, 2, 6, 7 </span>→ 2, 3, 3, 4, 4, 6, 7, 8, 8, 8
<span>mean: 5.3
range: 6
The boys have the higher range while the girls have the higher mean value.
</span><span>
</span>
Step-by-step explanation:
Given equation is
2y = 3x + 10
3x - 2y + 10 = 0 .....i)
Any line parallel to line I) is
3x - 2y + k = 0 ......ii)
As the line two passes through the point ( 2 , - 5 ) Now substituting the values
3 * 2 - 2 * ( - 5) + k = 0
6 + 10 + k = 0
16 + k = 0
k = - 16
Now putting the value of k in equation two
3x - 2y + 16 = 0 is the required equation.
Hope it will help :)❤
Answer:
D 3.5
Step-by-step explanation:
Replace values in the equation with values given. Calculate.
Answer:
A
Step-by-step explanation:
