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nlexa [21]
3 years ago
14

The sugar content of the syrup in canned peaches is normally distributed. A random sample of n = 10 cans yields a sample standar

d deviation of s = 4.848 milligrams. Construct a 95% two-sided confidence interval for σ. Round your answers to 2 decimal places.
Mathematics
1 answer:
meriva3 years ago
5 0

Answer:

95% Confidence interval of the standard deviation: 3.33 ≤ σ ≤ 8.85

Step-by-step explanation:

Sample size = 10

Degrees of freedom = 10-1 = 9

For a 95% confidence interval, we have  α=0.05, which gives 2.5% of the area at each end of the chi-square distribution.

We calculate the chi-square values for a 95% confidence interval

Value of chi-square_0.975 = 2.70

Value of chi-square_0.025 = 19.02

We then evaluate [tex]\sqrt{ \frac{(n-1)*s^{2} }{X^{2} }}[/tex] for the two values of chi-square.

Then we have:

[tex]\sqrt{\frac{(n-1)*s^{2} }{X^{2}}} =\sqrt{\frac{(10-1)*4.848^{2} }{2.70}}=\sqrt{78.34}=8.85\\\\\\sqrt{\frac{(n-1)*s^{2} }{X^{2}}} =\sqrt{\frac{(10-1)*4.848^{2} }{19.02}}=\sqrt{11.12}=3.33[/tex]

With these results we can express the confidence interval as

3.33 ≤ σ ≤ 8.85

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3 years ago
PLEASE HELP FAST I NEED THIS QUICKLY
son4ous [18]

Answer:

0.833

Step-by-step explanation:

1. locate which vertical column of the graph we are referring to:

  • student 7

2. calculate the total number of trials student 7 did:

  • if in 5 trials the tack landed point-up, and in 1 trial the tack did not land point-up, the total number of trials is 6
  • 5 + 1 = 6

3. refer back to the question:

  • the question states: "what is the experimental probability that the tack lands point-up"

4. interpret the graph:

  • of the 6 trials student 7 underwent, the graph tells us that 5 landed point-up.
  • therefore the experimental probability of a tack landing point up is 5/6 (in 5 out of the 6 trials, the tack landed point-up)

5. converting from fraction to decimal:

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therefore, the experimental probability that the tack will land point-up, is 0.833

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