Question

Graph the first six terms of a sequence where a1 = 4 and r = 2.

Answer 1

Answer:

So the sequence will be 4, 8, 16, 32, 64, 128 .......

Step-by-step explanation:

We have to graph the first six terms of a sequence with first term a = 4 and r = 2 Since r denotes common ratio so the given sequence is a geometric sequence.

Now we know the explicit formula for a geometric sequence is

$T_{(n)}=a(r)^{n-1}$

Since   $T_{1}$ = 4

So        $T_{2}=4(2)^{2-1}$ = 4 × 2 = 8

            $T_{3}=4(2)^{3-1}$ = 4 × 2² = 4 × 4 = 16

           $T_{4}=4(2)^{4-1}$ = $(4)(2)^{3}$ = 4 × 8 = 32

           $T_{5}=4(2)^{5-1}$ = $4(2)^{4}$ = 4 × 16 = 64

           $T_{6}=4(2)^{6-1}$ = $4(2)^{5}$ = 4 × 32 = 128

So the sequence will be 4, 8, 16, 32, 64, 128 .......

Answer 2

Answer:

1. Graph the first six terms of a sequence where a1 = 3 and d = −10. 2. Graph the first six terms of a sequence where

a1 =

4

and r

= 2. 3. Graph the six terms of a finite series where a1 = −3...

Step-by-step explanation: