1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
Dmitry_Shevchenko [17]
3 years ago
5

Steven put together 981 pieces of a puzzle. About how many pieces did he put together? Round to the nearest thousand. Use what y

ou know about place value to explain your answer.
Mathematics
1 answer:
Colt1911 [192]3 years ago
3 0
About 1,000 puzzle pieces
You might be interested in
Yomaro is buying soil for his garden. He needs to fill one pot with 12 cups of soil and another pot with 2 gallons of soil.
SOVA2 [1]

Answer the answer to your question is $7.50

3 0
3 years ago
Mike and Beatrice purchase a house for $200,000. If the equation V = 200,000(1.03)x represents the value of the house after x ye
notsponge [240]
X=((log(225000/200000)/log(1.03))
X=log(225,000÷200,000)÷log(1.03)
X=3.98 years
6 0
4 years ago
Read 2 more answers
Which expression is equivalent to(2^3)^-5
Nady [450]

Answer:

hope this helps if not im sorry

Step-by-step explanation:

(2^3)^5

=2^(3*5)

= 2^15

3 0
3 years ago
According to​ psychologists, IQs are normally​ distributed, with a mean of 100 and a standard deviation of 15 . a. What percenta
Angelina_Jolie [31]
Answer: 34%.

By definition of normal distribution, ≈68% of the data is within 1 standard deviation of the mean. Therefore 68% of IQs are between 85 and 115, and half of that is on the lower end, 85 to 100.
3 0
3 years ago
PRECAL:<br> Having trouble on this review, need some help.
ra1l [238]

1. As you can tell from the function definition and plot, there's a discontinuity at x = -2. But in the limit from either side of x = -2, f(x) is approaching the value at the empty circle:

\displaystyle \lim_{x\to-2}f(x) = \lim_{x\to-2}(x-2) = -2-2 = \boxed{-4}

Basically, since x is approaching -2, we are talking about values of x such x ≠ 2. Then we can compute the limit by taking the expression from the definition of f(x) using that x ≠ 2.

2. f(x) is continuous at x = -1, so the limit can be computed directly again:

\displaystyle \lim_{x\to-1} f(x) = \lim_{x\to-1}(x-2) = -1-2=\boxed{-3}

3. Using the same reasoning as in (1), the limit would be the value of f(x) at the empty circle in the graph. So

\displaystyle \lim_{x\to-2}f(x) = \boxed{-1}

4. Your answer is correct; the limit doesn't exist because there is a jump discontinuity. f(x) approaches two different values depending on which direction x is approaching 2.

5. It's a bit difficult to see, but it looks like x is approaching 2 from above/from the right, in which case

\displaystyle \lim_{x\to2^+}f(x) = \boxed{0}

When x approaches 2 from above, we assume x > 2. And according to the plot, we have f(x) = 0 whenever x > 2.

6. It should be rather clear from the plot that

\displaystyle \lim_{x\to0}f(x) = \lim_{x\to0}(\sin(x)+3) = \sin(0) + 3 = \boxed{3}

because sin(x) + 3 is continuous at x = 0. On the other hand, the limit at infinity doesn't exist because sin(x) oscillates between -1 and 1 forever, never landing on a single finite value.

For 7-8, divide through each term by the largest power of x in the expression:

7. Divide through by x². Every remaining rational term will converge to 0.

\displaystyle \lim_{x\to\infty}\frac{x^2+x-12}{2x^2-5x-3} = \lim_{x\to\infty}\frac{1+\frac1x-\frac{12}{x^2}}{2-\frac5x-\frac3{x^2}}=\boxed{\frac12}

8. Divide through by x² again:

\displaystyle \lim_{x\to-\infty}\frac{x+3}{x^2+x-12} = \lim_{x\to-\infty}\frac{\frac1x+\frac3{x^2}}{1+\frac1x-\frac{12}{x^2}} = \frac01 = \boxed{0}

9. Factorize the numerator and denominator. Then bearing in mind that "x is approaching 6" means x ≠ 6, we can cancel a factor of x - 6:

\displaystyle \lim_{x\to6}\frac{2x^2-12x}{x^2-4x-12}=\lim_{x\to6}\frac{2x(x-6)}{(x+2)(x-6)} = \lim_{x\to6}\frac{2x}{x+2} = \frac{2\times6}{6+2}=\boxed{\frac32}

10. Factorize the numerator and simplify:

\dfrac{-2x^2+2}{x+1} = -2 \times \dfrac{x^2-1}{x+1} = -2 \times \dfrac{(x+1)(x-1)}{x+1} = -2(x-1) = -2x+2

where the last equality holds because x is approaching +∞, so we can assume x ≠ -1. Then the limit is

\displaystyle \lim_{x\to\infty} \frac{-2x^2+2}{x+1} = \lim_{x\to\infty} (-2x+2) = \boxed{-\infty}

6 0
2 years ago
Other questions:
  • A rectangular prism has a height of 4 and a half cubic inches if the length of the prism is eight and a half inches and the widt
    5·1 answer
  • La longitud de 36.27? Porfavor
    10·1 answer
  • Pls help with algebra 2 semester 1 2.4.1 quiz
    9·1 answer
  • How to turn 7/50 into a decimal
    13·2 answers
  • Arnie is mixing red and yellow paints to make two different shades of orange. To make 1 cup of dark orange​ paint, he needs 7 ou
    15·1 answer
  • I need help with this
    7·1 answer
  • Please help, ill give brainliest!
    9·1 answer
  • Indicate whether there is exactly one solution, infinitely many solutions, or no solution to the equation shown.
    12·2 answers
  • Duo makes 65% of his dumplings vegetarian fillings. what fraction have vegetarian fillings?​
    13·2 answers
  • Find the volume of this.<br> Show work.
    10·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!