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MAVERICK [17]
3 years ago
13

Give coordinates for any three points that are on the same horizontal line. Include at least one point that has a fraction as a

coordinate.
Mathematics
1 answer:
myrzilka [38]3 years ago
3 0

Answer:

\left(1, 2\right), \left(\frac{7}{2}, 2\right) and \left(6, 2\right).

Step-by-step explanation:

Any point in coordinate system has a x-coordinate and a y-coordinate. In coordinate system any point p will be represented as p(x-coordinate, y-coordinate).

Any three points in coordinate system will lie on the same horizontal line if they have same values for their y-coordinate. While the values for x-coordinate for these points should be different.

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Miss Taylor graded 50 English research papers. Twelve of them received a grade of A. Miss Taylor drew a circle graph to display
nikdorinn [45]
<h3>Answer:</h3>

\large\boxed{24\%}

<h3>Step-by-step explanation:</h3>

In this question, it's asking you to find how much percentage the circle graph is for "A" papers.

To solve this question, we would need to use information from the question.

Important information:

  • Graded 50 English research papers
  • 12 of those papers had an "A" grade

With the information above, we can solve the question.

We know that there are 12 research papers that received an A and there are 50 research papers in total.

We would divide 12 by 50 in order to find the percentage of the papers that got an A.

12\div50=24

When you divide, you should get 24.

This means that 24% of the circle graph is devoted to "A" papers.

<h3>I hope this helped you out.</h3><h3>Good luck on your academics.</h3><h3>Have a fantastic day!</h3>
3 0
3 years ago
NEED HELP HERE ASAP<br><br> 6. Find the cube roots of 27(cos 330° + i sin 330°).
VLD [36.1K]
<span>we have that

the cube roots of 27(cos 330° + i sin 330°) will be
</span>∛[27(cos 330° + i sin 330°)]

we know that
e<span>^(ix)=cos x + isinx
therefore
</span>∛[27(cos 330° + i sin 330°)]------> ∛[27(e^(i330°))]-----> 3∛[(e^(i110°)³)]
3∛[(e^(i110°)³)]--------> 3e^(i110°)-------------> 3[cos 110° + i sin 110°]

z1=3[cos 110° + i sin 110°]

 cube root in complex number, divide angle by 3
360nº/3 = 120nº --> add 120º for z2 angle, again for z3
<span>therefore
</span>
z2=3[cos ((110°+120°) + i sin (110°+120°)]------ > 3[cos 230° + i sin 230°]

z3=3[cos (230°+120°) + i sin (230°+120°)]--------> 3[cos 350° + i sin 350°]
<span>
the answer is 

</span>z1=3[cos 110° + i sin 110°]<span>

</span>z2=3[cos 230° + i sin 230°]

z3=3[cos 350° + i sin 350°]<span>

</span>
7 0
4 years ago
Which value is an input of the function? –14 –2 0 4
Nina [5.8K]

Answer:

the value is 4.

Step-by-step explanation:

8 0
4 years ago
What is the slope of the line that passes through the points (-7, -7) and (-7, 1) ?
ICE Princess25 [194]

Answer:

undefined

Step-by-step explanation:

(-7, -7) and (-7, 1)

To find the slope of the line, we use the slope formula: (y₂ - y₁) / (x₂ - x₁)

Plug in these values:

(1 - (-7)) / (-7 - (-7))

Simplify the parentheses.

= (1 + 7) / (-7 + 7)

Simplify the fraction.

8/0

= undefined

Our line is a vertical line, which has an undefined slope.

Hope this helps!

6 0
3 years ago
HELPPPP
Yuki888 [10]

Dilation about the origin multiplies every coordinate by the scale factor.

C' = 4(-5, 2) = (-20, 8)

A' = 4(-4, 4) = (-16, 16)

T' = 4(-1, 2) = (-4, 8)

7 0
3 years ago
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