f(x) being even means
f(x) = f(-x)
So the zeros come in positive and negative pairs. If there are an odd number of intercepts like there are here, it's because one of them is x=0 which is its own negation.
Given zero x=6 we know x=-6 is also a zero.
So we know three zeros, and know the other two zeros are a positive and negative pair.
The only choice with (-6,0) and (0,0) is A.
Choice A
Is there another part of this?
Answer:
B) ASA
Step-by-step explanation:
The ASA (Angle-Side-Angle) postulate states that if two angles and the included side of one triangle are congruent to two angles and the included side of another triangle, then the triangles are congruent. (The included side is the side between the vertices of the two angles)
In this case, angle U, side UY and angle Y are congruent to angle U, side UW and angle W
Y ≤ x - 5
y ≥-x - 4
x - 5 = -x - 4
+ x + x
2x - 5 = -4
+ 5 + 5
2x = 1
2 2
x = ¹/₂
y = x - 5
y = ¹/₂ - 5
y = -4¹/₂
The following points that lie in the solution set to the following system of inequalities is (¹/₂, -4¹/₂).
Since 25/10 is 2.5 I think you can multiply 6 by 2.5 and get 15 so I think it’s about 15/25
