Answer:
The other endpoint of the segment is
.
Step-by-step explanation:
The midpoint of the points
and
is given by the following formula:

where
= coordinates of the midpoint.
We know that the midpoint is (-15, 2) and an endpoint is (-12, 11). Substituting the information we have gives:

To find
we need to solve this equation:

and to find
we need to solve this equation:

The other endpoint of the segment is
.
Answer:3/19
Step-by-step explanation:
5/19 - 2/19 = 3/19
Cuando has simplificado la ecuación lo mas posible y las expresiones de los dos lados quedan iguales, hay soluciones infinitas. Pero, dado que lo has simplificado y son diferentes, no hay solución.
1.) 7x = 12 + 7x - 12
=> 7x = 7x => infinita solución
2.) x - 11 = 11 + x
=> x = 22 + x => no solución
3.) 2(4x - 6) = 8(x + 2)
=> 8x - 12 = 8x + 16 => 8x = 8x + 28 => no solución
4.) 2x - 9 = 2x - 9
=> infinita solución
5.) 8 + 4x = 4x + 10
=> 4x = 4x - 2 => no solución
Divide 8.5 by .3 and get 28.3333. She can't make tacos with the extra .3 pounds so the answer is 28 tacos
Question:
Consider the sequence of numbers: 
Which statement is a description of the sequence?
(A) The sequence is recursive, where each term is 1/4 greater than its preceding term.
(B) The sequence is recursive and can be represented by the function
f(n + 1) = f(n) + 3/8 .
(C) The sequence is arithmetic, where each pair of terms has a constant difference of 3/4 .
(D) The sequence is arithmetic and can be represented by the function
f(n + 1) = f(n)3/8.
Answer:
Option B:
The sequence is recursive and can be represented by the function

Explanation:
A sequence of numbers are

Let us first change mixed fraction into improper fraction.

To find the pattern of the sequence.
To find the common difference between the sequence of numbers.




Therefore, the common difference of the sequence is 3.
That means each term is obtained by adding
to the previous term.
Hence, the sequence is recursive and can be represented by the function