Find the zero of the following function.f(x)=x³-7x²+4x+12
1 answer:
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Answer:
5. 25/36
6. 25/36
7. -3/4 or 6
8. 0 or 4
Step-by-step explanation:
5. Square both sides: x + 4 = 9 - 6 + x
Subtract x from both sides and subtract 9 from both sides:
-5 = -6
Square both sides again: 25 = 36x
Divide both sides by 36: x = 25/36
6. Square both sides: x + 4 = 9 + 6 + x
Subtract x and 9 from both sides: -5 = 6
Square both sides: 25 = 36x
Divide both sides by 36: x = 25/36
7. Square both sides: x + 3 = 5x + 6 - 6 + 9
Add 6 to both sides and isolate it: 6
= 4x + 12
Divide both sides by 2 and then square both sides again:
3 = 2x + 6
9 * (5x + 6) = 4x^2 + 24x + 36
45x + 54 = 4x^2 + 24x + 36
4x^2 - 21x - 18 = 0
Factorize: (4x + 3)(x - 6) = 0 ⇒ x = -3/4 or x = 6
8. Square both sides: 2x + 1 = x^2 - 2x + 1
Move all the terms to one side and combine like terms: x^2 - 4x = 0
Factorize: x(x - 4) = 0 ⇒ x = 0 or x = 4
Hope this helps!