Question

Find the zero of the following function.f(x)=x³-7x²+4x+12 ​

Answer 1

Answer:

Step-by-step explanation:

Hello, we can notice that f(-1)=0 so (x+1) is a factor and we can write.

$f(x)=(x+1)(x^2-8x +12)\\\\=(x+1)(x-6)(x-2)$

The sum of the zeros is 8=6+2 and the product is 12=6*2

So the zeroes are 2, 6, -1

thanks