Answer:
Step-by-step explanation:
The initial height of a Japanese maple sapling is 14 inches.
The tree is expected to grow 2.5 inches each month. This increase in height is linear, thus it is in arithmetic progression.
The expression for arithmetic progression is
Tn = a + (n-1)d
Where a = the first term of the series
d = common difference
Tn is the nth term of the series
n = the number of terms.
From the information given
a = 14 inches because it is the initial height of the tree
d = 2.5 because it is the difference in height between 2 consecutive months
n = m( number of months)
Tn = f(m)
function models the relationship between the height of the tree f(m) and the number of m months of growth will be
f(m) = 14 + 2.5(m-1)
Answer:
-2
Step-by-step explanation:
Answer:
The values of x for which the model is 0 ≤ x ≤ 3
Step-by-step explanation:
The given function for the volume of the shipping box is given as follows;
V = 2·x³ - 19·x² + 39·x
The function will make sense when V ≥ 0, which is given as follows
When V = 0, x = 0
Which gives;
0 = 2·x³ - 19·x² + 39·x
0 = 2·x² - 19·x + 39
0 = x² - 9.5·x + 19.5
From an hint obtained by plotting the function, we have;
0 = (x - 3)·(x - 6.5)
We check for the local maximum as follows;
dV/dx = d(2·x³ - 19·x² + 39·x)/dx = 0
6·x² - 38·x + 39 = 0
x² - 19/3·x + 6.5 = 0
x = (19/3 ±√((19/3)² - 4 × 1 × 6.5))/2
∴ x = 1.288, or 5.045
At x = 1.288, we have;
V = 2·1.288³ - 19·1.288² + 39·1.288 ≈ 22.99
V ≈ 22.99 in.³
When x = 5.045, we have;
V = 2·5.045³ - 19·5.045² + 39·5.045≈ -30.023
Therefore;
V > 0 for 0 < x < 3 and V < 0 for 3 < x < 6.5
The values of x for which the model makes sense and V ≥ 0 is 0 ≤ x ≤ 3.
Answer:
C
Step-by-step explanation:
S(5) = -16*(5)*2 + 550 = 390
you just replace t with 5
