What is an equation of the line that passes through the point (-6,-3) and is parallel to the line 5x-3y=9?
1 answer:
Answer:y=5x/3 +7
Step-by-step explanation:
First, we find the slope of the line parallel. That is clearly, by rearranging, -3y= -5x + 9, and then dividing by -3, the slope is 5/3 .
Now, we know our equation is in the form of y = 5x/3 + b. Plugging in (-6,-3), we have -3 = -10 + b, so b = 7. Therefore, our equation is y= 5x/3 +7.
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