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Ahat [919]
3 years ago
8

What is an equation of the line that passes through the point (-6,-3) and is parallel to the line 5x-3y=9?

Mathematics
1 answer:
irina [24]3 years ago
6 0

Answer:y=5x/3 +7

Step-by-step explanation:

First, we find the slope of the line parallel. That is clearly, by rearranging, -3y= -5x + 9, and then dividing by -3, the slope is 5/3 .

Now, we know our equation is in the form of y = 5x/3 + b. Plugging in (-6,-3), we have -3 = -10 + b, so b = 7. Therefore, our equation is y= 5x/3 +7.

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A garden hose supplies 36 gallons of water in 3 minutes. What is the garden hose's water flow in gallons per minute.
Ne4ueva [31]

Answer:

12

Step-by-step explanation:

36/3 =12

8 0
2 years ago
Hope an expert can help with this
Citrus2011 [14]

For Range you take the biggest number and subtract it with the smallest. So:

January = E14,000

Febuary = E9,000

March = E10,000

All Three Months = E17,000

Hope this helps,pleeease vote as brainliest!

5 0
3 years ago
What is the answer????
dem82 [27]
E I think I am not sure though.
6 0
2 years ago
He rain caused the river to ride a total of 6 2/3 inches. The river was rising at an average of 2/3 of an inch each hour. How ma
Kobotan [32]
To find out how many hours it rained, divide the total rise in the river by the amount it rose every hour.

\sf 6\dfrac{2}{3}\div\dfrac{2}{3}

First convert the mixed number into an improper fraction. We do this by multiplying the denominator to the whole number, adding it to the numerator, which becomes our new numerator, and we keep the denominator the same:

\sf\dfrac{20}{3}\div\dfrac{2}{3}

When dividing fractions we flip(the reciprocal) the one we're dividing by and multiply:

\sf\dfrac{20}{3}\times\dfrac{3}{2}

Multiply the numerators and denominators together:

\sf\dfrac{60}{6}

Simplify by dividing:

\boxed{\sf 10}

So it rained for 10 hours.
5 0
3 years ago
Which is the value of this expression when a=5 and k=-2
Zinaida [17]

Answer:

Option C is correct.

Step-by-step explanation:

We are given the expression:

(\frac{3^2a^{-2}}{3a^{-1}})^k

The value of a =5 and k = -2

Putting the values and solving

=(\frac{3^2*5^{-2}}{3*5^{-1}})^-2\\=(\frac{3^{2-1}}{5^{-1+2}})^-2\\=(\frac{3^{1}}{5^{1}})^-2\\\\=(\frac{3}{5})^-2\\if \,\,a^{-1} \,\,then\,\, 1/a\\=\frac{(3)^{-2}}{(5)^{-2}}\\ Can\,\,be\,\,written\,\,as\\\\=\frac{(5)^{2}}{(3)^{2}} \\=\frac{25}{9}

Option C is correct.

3 0
2 years ago
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