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3 years ago

HURRY!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!

2 answers:

7 0

<span>A) The effort force is always smaller than the force needed without the machine.

It is because some of the work (by force) is lost during the conversion

Hope this helps!</span>

Triss [41]3 years ago

5 0

<span>A) The effort force is always smaller than the force needed without the machine. </span>

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Consult Multiple-Concept Example 5 for insight into solving this problem. A skier slides horizontally along the snow for a dista

Gennadij [26K]

Answer:

The speed with which the skier was going is approximately 2.9906 m/s

Explanation:

The given parameters are;

The distance the skier slides before coming to rest, s = 12.4 m

The coefficient of friction between the skier and the snow, $\mu _k$ = 0.0368

Therefore, for conservation of energy, we have;

Initial kinetic energy = Work done by the kinetic friction force

Initial kinetic energy = 1/2·m·v²

The work done by the kinetic friction force = $\mu _k$ ×m×g×s

Where;

m = The mass of the skier

v = The speed with which the skier was going

g = The acceleration due to gravity = 9.8 m/s²

s = The distance the skier slides before coming to rest = 12.4 m

$\mu _k$ = The kinematic friction = 0.0368

Therefore, for conservation of energy, we have;

1/2·m·v² = $\mu _k$ ×m×g×s

1/2·v² = $\mu _k$ ×g×s

v² = 2× $\mu _k$ ×g×s = 2 × 0.0368 × 9.8 × 12.4 = 8.943872

v = √(8.943872) ≈ 2.99063070271 ≈ 2.9906 m/s

The speed with which the skier was going = v ≈ 2.9906 m/s.

3 0

3 years ago

A permanent magnet is placed near a bar of soft iron PQ what will happen

boyakko [2]

Answer:

it will rust

Explanation:

hope it helps

4 0

3 years ago

A meter stick is found to balance at the 49.7-cm mark when placed on a fulcrum. When a 41.5-gram mass is attached at the 28.5-cm

zzz [600]

Answer:

The value is $M = 42.3 \ kg$

Explanation:

From the question we are told that

The first position of the fulcrum is x = 49.7 cm

The mass attached is $m = 41.5 \ g$

The position of the attachment is $x_1 = 28.5 \ cm$

The second position of the fulcrum is $x_2 = 39.2 \ cm$

Generally the sum of clockwise torque = sum of anti - clockwise torque

$CWT = m (x_2 - x_1)$

Here CWT stands for clockwise torque

$ACWT = M ( x - x_2)$

$m (x_2 - x_1) = M ( x - x_2)$

=> $41.5 (39.2 - 28.5 ) = M ( 49.7 -39.2 )$

=> $M = 42.3 \ kg$

3 0

3 years ago

A charge of +0.08 C moves to the right due to a 4 N force exerted by an electric field. What is the magnitude and direction of t

Otrada [13]

This is late but the answer is 50 n/c right

4 0

3 years ago

Read 2 more answers

When an atom absorbs energy the electrons move from their?

alukav5142 [94]

Atom absorbs energy when it goes into higher orbitals from their "Ground States"

Hope this helps!

8 0

4 years ago