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4 years ago

Pressing two objects together with more force ______ friction.

Physics

2 answers:

Artyom0805 [142]4 years ago

8 0

A is your answer and the other choices are wrong ...

G..

Alenkinab [10]4 years ago

5 0

Answer : Option A) Increases.

Explanation : Pressing two objects together with more force will increase the friction.

Friction is defined as the resistance to motion of an object which is relative to another.

If the forces acting between the two objects are found to be vertical then they will have an effect of increased friction as they increase the weight.

When forces are assumed to be horizontal then, the result of weight gets multiplied by the coefficient of friction which will result in having no effect on the friction.

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Kingda Ka has a maximum speed of 57.2 m/s. Determine the height of the hill on this roller coaster. Explain to get full credit,

kodGreya [7K]

This question involves the concepts of the law of conservation of energy, kinetic energy, and potential energy.

The height of the hill is "166.76 m".

<h3>LAW OF CONSERVATION OF ENERGY:</h3>

According to the law of conservation of energy at the highest point of the roller coaster ride, that is, the hill, the whole (maximum) kinetic energy of the roller coaster is converted into its potential energy:

$Maximum\ Kinetic\ Energy\ Lost = Maximum\ Potential\ Energy\ Gain\\\\
\frac{1}{2}mv_{max}^2=mgh\\\\
h=\frac{v_{max}^2}{2g}$

where,

h = height of the hill = ?

$v_{max}$ = maximum velocity = 57.2 m/s

g = acceleration due to gravity = 9.81 m/s²

Therefore,

$h=\frac{(57.2\ m/s)^2}{2(9.81\ m/s^2)}\\\\
$

Learn more about the law of conservation of energy here:

brainly.com/question/101125

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3 years ago

Two gliders collide on an air track moving in from opposite directions, and they bounce back. The masses of the gliders are 0.20

timurjin [86]

Answer:

so initial momentum is 0.22kgm/s

Explanation:

m1=0.20kg

m2=0.30kg

initial velocity of m1=u1=0.50m/s

initial velocity of m2=u2=0.40m/s

total momentum of the system before collision

Pi=m1u1+m2u2

Pi=0.20kg×0.50m/s+0.30kg×0.40m/s

Pi=0.1kgm/s+0.12kgm/s

Pi=0.22kgm/s

3 0

4 years ago

Can the velocity of a body revese the direction when acceleration is constant?

TEA [102]

Answer:

Yes, the velocity of the object can reverse direction when its acceleration is constant. For example consider that the velocity of any object at any time t is given as: ... At At t = 0 sec, the magnitude of velocity is 2m/s and is moving in the forward direction i.e.v (t) = -2.

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3 years ago

Which of the following is a unit of volume in the English system of measurement? (4 points)

Levart [38]

The answer is gallons.

3 0

4 years ago

Read 2 more answers

A student stretches a spring, attaches a 1.20 kg mass to it, and releases the mass from rest on a frictionless surface. The resu

Sphinxa [80]

Answer:

the speed of the mass when it is halfway to the equilibrium position is 1.26 m/s

Explanation:

Given that;

mass of the object m = 1.20 kg

period of oscillation = 0.750 s

Amplitude ( A/x) = 15.0 cm = 0.15 m

now;

a) Determine the oscillation frequency;

oscillation frequency f = 1/T

we substitute

f = 1 / 0.750 s

f = 1.33 Hz

Therefore, the oscillation frequency is 1.33 Hz

b) Determine the spring constant;

we solve for spring constant from the following expression;

T = 2π√(m/k)

k = 4π²m / T²

so we substitute

k = (4π² × 1.20) / (0.750)²

k = 47.3741 / 0.5625

k = 84.22 N/m

Therefore, the spring constant is 84.22 N/m

c) determine the speed of the mass when it is halfway to the equilibrium position

So, at equilibrium, the energy is equal to K.E

such that;

1/2mv² = 1/2kx²

mv² = kx²

v² = kx² / m

v = √( kx²/m)

we substitute

v = √( 84.22×(0.15 m)²/ 1.2 )

v = √( 1.89495 / 1.2 )

v = √ 1.579125

v = 1.26 m/s

Therefore, the speed of the mass when it is halfway to the equilibrium position is 1.26 m/s

3 0

3 years ago