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Irina-Kira [14]

3 years ago

15

Chris also wants to hang string lights outside in his backyard. if each pack contains 96 inches of string lights how many packs

would he need to buy to line the perimeter of a 20ft by 12ft backyard?

1 answer:

netineya [11]3 years ago

7 0

Answer:

8 packs of street lights

Step-by-step explanation:

Perimeter - 64 ft

20 + 20 + 12 + 12

64

1 foot = 12 inches

1 pack = 96 inches or 8 feet

$\frac{64}{8} = 8$

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If sin(theta) =4/5 and is in quadrant 2, the value of cot(theta

iren [92.7K]

$\sin\theta= \frac{4}{5} 
\\
\\\sin^2\theta+\cos^2\theta=1
\\ \cos\theta=\pm \sqrt{1-\sin^2\theta} =\pm \sqrt{1-( \frac{4}{5})^2 } =\pm \sqrt{1- \frac{16}{25} } =\pm \sqrt{\frac{9}{25} }=\pm \frac{3}{5}}$

$\theta \in II \Rightarrow \cos\theta\ \textless \ 0 \Rightarrow \cos\theta=-\frac{3}{5}$

$\cot\theta= \frac{\cos\theta}{\sin\theta}= \frac{-\frac{3}{5}}{\frac{4}{5}} =- \frac{3}{4}$

5 0

3 years ago

10 tens and 10 ones equals

jenyasd209 [6]

Answer:

110 is the answer because 10 tens equal 100 and 10 ones equal 10

Step-by-step explanation:

8 0

3 years ago

Write an equation using the following numbers in the chart in point slope form

slavikrds [6]

Answer:

A

Step-by-step explanation:

3 0

3 years ago

Find each numbered angle measure:

stich3 [128]

Answer:

m∠1=77°

m∠2=36°

m∠3=30°

Step-by-step explanation:

First, find angle 1 by adding 66 and 37 and subtracting them from 180 because there are 180 degrees in an angle.

180-(66+37)=77°

You can then find angle 2 by finding the other angle not given. You can find this angle by subtracting 77 from 180, giving you 103. To find angle 2, add 103 and 41 and subtract them from 180.

180-(103+41)=36°

You can then find angle 3 by adding the angle 103 and the angle 47, and subtracting them from 180

180-(103+47)=30°

8 0

3 years ago

Suppose the equation for line A is given by 2x = 5y – 25. If line A and B are perpendicular

Ludmilka [50]

The required equation of line B is 2y+5x=-2

The equation of a line in point-slope form is expressed as:

y-y0 = m(x-x0)

m is the slope of the line

(x0, y0) is the point on the line

Given the line A expressed as:

2x = 5y – 25

Rewrite in standard form

5y = 2x + 25

y = 2/5 x + 5

The slope will be 2/5

The slope of the perpendicular line will be;

$M = \frac{-1}{(2/5)}\\M = \frac{-5}{2}$

Substitute the point (-6, 14) and slope -5/2 into the equation above to get the required equation of line B

$y-14=-5/2(x+6)\\2(y-14) = -5(x+6)\\2y-28=-5x-30\\2y+5x=-30+28\\2y+5x=-2\\$

Hence the required equation of line B is 2y+5x=-2

Learn more here: brainly.com/question/13140886

6 0

3 years ago