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3 years ago

Find the diffrence 3/4 - 1/3

Mathematics

2 answers:

kipiarov [429]3 years ago

4 0

Answer:

3 /4 – 1/3 = 5 /12

Step-by-step explanation:

Calculation steps:

3 /4 –1 /3

=3 × 3 /4 × 3–1 × 4/3 × 4

= 9 /12 –4 /12

= 9 – 4 /12

= 5 /12

gtnhenbr [62]3 years ago

3 0

Answer: 0.4

Step-by-step explanation: 3/4 - 1/3 = 5/12

converted to decimal: 5 ÷ 12 = 0.4

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A square mirror has sides measuring 2 ft less than the sides of a square painting. If the difference between their areas is 32 f

kari74 [83]

Answer: The side lengths of mirror and painting are 7 ft and 9 ft respectively.

Step-by-step explanation: Given that a square mirror has sides measuring 2 ft less than the sides of a square painting and the difference between their areas is 32 ft.

We are to find the lengths of the sides of the mirror and the painting.

Let x ft represents the length of the side of mirror. Then, the side length of square painting is (x+2) ft.

According to the given information, we have

$\textup{area of painting}-\textup{area of mirror}=32\\\\\Rightarrow (x+2)^2-x^2=32\\\\\Rightarrow x^2+4x+4-x^2=32\\\\\Rightarrow 4x=28\\\\\Rightarrow x=\dfrac{28}{4}\\\\\Rightarrow x=7.$

Therefore, the side length of mirror is 7 ft and the side length of painting is (7+2) = 9 ft.

Thus, the side lengths of mirror and painting are 7 ft and 9 ft respectively.

5 0

3 years ago

What is 11% of 15? 1.65 1.56 2.5

Vesna [10]

1.5 +.15 = 1.65. 10% x 15 + 1% x 15

6 0

2 years ago

Find the area of the given shape

mel-nik [20]

Answer:

Here are some formulas and some info to get you started:

Step-by-step explanation:

Parallelogram:

Area = Base · Height

Triangle:

Area = 1/2 · Base · Height

Know that the height is the vertical dotted line. Also know that the horizontal dotted line attached to the base is not actually part of the base.

If you need any more help let me know, and good luck!

6 0

3 years ago

(X^2+y^2+x)dx+xydy=0 Solve for general solution

aksik [14]

Check if the equation is exact, which happens for ODEs of the form

$M(x,y)\,\mathrm dx+N(x,y)\,\mathrm dy=0$

if $\frac{\partial M}{\partial y}=\frac{\partial N}{\partial x}$ .

We have

$M(x,y)=x^2+y^2+x\implies\dfrac{\partial M}{\partial y}=2y$

$N(x,y)=xy\implies\dfrac{\partial N}{\partial x}=y$

so the ODE is not quite exact, but we can find an integrating factor $\mu(x,y)$ so that

$\mu(x,y)M(x,y)\,\mathrm dx+\mu(x,y)N(x,y)\,\mathrm dy=0$

is exact, which would require

$\dfrac{\partial(\mu M)}{\partial y}=\dfrac{\partial(\mu N)}{\partial x}\implies \dfrac{\partial\mu}{\partial y}M+\mu\dfrac{\partial M}{\partial y}=\dfrac{\partial\mu}{\partial x}N+\mu\dfrac{\partial N}{\partial x}$

$\implies\mu\left(\dfrac{\partial N}{\partial x}-\dfrac{\partial M}{\partial y}\right)=M\dfrac{\partial\mu}{\partial y}-N\dfrac{\partial\mu}{\partial x}$

Notice that

$\dfrac{\partial N}{\partial x}-\dfrac{\partial M}{\partial y}=y-2y=-y$

is independent of x, and dividing this by $N(x,y)=xy$ gives an expression independent of y. If we assume $\mu=\mu(x)$ is a function of x alone, then $\frac{\partial\mu}{\partial y}=0$ , and the partial differential equation above gives