All categories

3 years ago

Please can you help me I don't understand

Mathematics

1 answer:

Alexxx [7]3 years ago

8 0

I will show you how to do the first one.....we are finding the GCF...the largest number that goes into each number (same for variables)

1.) 20yx , 80x³ ( factor each number and variable)

20 = 2, 4, 5, 10, 20
y = y
x = x
80 = 2, 4, 5, 8, 10, 16, 20, 40, 80
x³ = x, x, x

what is the largest number that 20 and 80 have in common? 20...
how about the variables? x

so, the Greatest Common Factor (GCF is 20x)

You might be interested in

How do you find the rate of change in a graph

Anni [7]

To find the unit rate, divide the numerator and denominator of the given rate by the denominator of the given rate

6 0

3 years ago

Read 2 more answers

NEED TO KNOW ASAP PLEASE HELP

AnnyKZ [126]

Answer:

You are <em>squaring x and -5 on the first equation</em>, and on the second equation you are <em>just squaring x and subtracting 5.</em>

Step-by-step explanation:

And since on the first equation x and -5 are in parenthesis that means that the square goes to both of them.

And the second one there is no parenthesis so the square only goes to the x.

I hope this helps you.

5 0

3 years ago

F(x)=x^3-2x+6 g(x)=2x^3+3x^2-4x+2 Find (f-g)(x).

____ [38]

(f-g)(x) = f(x) - g(x)
= (x^3 -2x+6) - (2x^3+3x^2-4x+2)
= x^3 -2x +6 -2x^3 -3x^2 +4x -2 . . . . distribute the negative sign
= (1-2)x^3 -3x^2 +(-2+4)x +(6-2) . . . . . combine like terms

(f-g)(x) = -x^3 -3x^2 +2x +4

7 0

3 years ago

In a metal fabrication process, metal rods are produced to a specified target length of 15 feet. Suppose that the lengths are n

Leto [7]

Answer:

95% Confidence interval: (14.4537 ,15.1463)

Step-by-step explanation:

We are given the following in the question:

Population mean, μ = 15 feet

Sample mean, $\bar{x}$ = 14.8 feet

Sample size, n = 16

Alpha, α = 0.05

Sample standard deviation, σ = 0.65 feet

Degree of freedom = n - 1 = 15

95% Confidence interval:

$\bar{x} \pm t_{critical}\displaystyle\frac{s}{\sqrt{n}}$

Putting the values, we get,

$t_{critical}\text{ at degree of freedom 15 and}~\alpha_{0.05} = \pm 2.1314$

$14.8 \pm 2.1314(\dfrac{0.65}{\sqrt{16}} ) \\\\= 14.8 \pm 0.3463 = (14.4537 ,15.1463)$

is the required confidence interval for the true mean length of rods.

3 0

3 years ago

Read 2 more answers

A sample is selected from a population with μ = 46, and a treatment is administered to the sample. After treatment, the sample m

Georgia [21]

Answer:

0.5

Step-by-step explanation:

Solution:-

- The sample mean before treatment, μ1 = 46

- The sample mean after treatment, μ2 = 48

- The sample standard deviation σ = √16 = 4

- For the independent samples T-test, Cohen's d is determined by calculating the mean difference between your two groups, and then dividing the result by the pooled standard deviation.

Cohen's d = $\frac{u2 - u1}{sd_p_o_o_l_e_d}$