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3 years ago

Points!!!!!

Computers and Technology

2 answers:

vfiekz [6]3 years ago

7 0

Answer:

b.the process of creating a vector image

Explanation:

because if we have a non-vector image or rasterize image, We should convert that rasterize image to vector to make the object salable.

Dominik [7]3 years ago

6 0

Answer:

The answer below is wrong

Explanation:

You might be interested in

What is thesql command to list the total sales by customer , month , and product, with subtotals by customer and by month and a

alexira [117]

Answer:

The answer is below

Explanation:

The the sql command to list the total sales by customer , month , and product, with subtotals by customer and by month and a grand total for all product sales is:

SELECT S.CUS_CODE, T.TM_MONTH, S.P_CODE,

SUM(S.SALE_UNITS*S.SALE_PRICE) AS "TOTSALES"

FROM DWDAYSALESFACT AS S INNER JOIN DWTIME AS T ON S.TM_ID =

T.TM_ID

GROUP BY S.CUS_CODE,T.TM_MONTH,S.P_CODE WITH ROLLUP;

4 0

3 years ago

A(n) ____ is a computer that requests and uses network resources from a(n) ____.

Crazy boy [7]

A(n) client exists a computer that requests and utilizes network resources from a(n) server.

<h3>What is a computer network?</h3>

A computer network is a collection of computers that share resources that are available on or provided by network nodes.
The computers communicate with one another via digital links using standard communication protocols.
These links are made up of telecommunication network technologies that are based on physically wired, optical, and wireless radio-frequency means and can be configured in a variety of network topologies.
Nodes in a computer network can be personal computers, servers, networking equipment, or other specialized or general-purpose hosts.
They can be identified by network addresses and have hostnames.
Local-area networks (LANs) and wide-area networks (WANs) are the two basic network types.

A(n) client exists a computer that requests and utilizes network resources from a(n) server.

To learn more about computer network, refer to:

brainly.com/question/8118353

#SPJ4

6 0

1 year ago

Greedy Algorithm Design

Alik [6]

Answer:

The algorithm is as follows:

1. Start

2. Get the number of items (n)

3. Get the current price of the n items (a1, a2..... an)

4. Get the possible hiked price of the n items (b1, b2..... bn)

5. Calculate the difference between the current and hiked prices for each item i.e. $d_i = b_i - a_i$

6. Sort the differences in descending order (i.e. from the greatest to the least)

7. Buy items in this order of difference

8. Stop

Explanation:

The algorithm is self-explanatory; however, what it does is that:

It takes a list of the current price of items (say list a)

E.g: $a = [100, 150, 160]$

Then take a list of the hiked price of the items (say list b)

E.g: $b = [110, 180, 165]$

Next, it calculates the difference (d) between corresponding prices $d_i = b_i - a_i$

$d = [(110 - 100),(180-150),(165-160)]$

$d = [10,30,5]$

Sort the difference from greatest to lowest (as the difference is sorted, lists a and b are also sorted)

$d = [30,10,5]$

$a = [150, 100, 160]$

$b = [180, 110, 165]$

If there is no hike up to item k, the couple would have saved (i = 1 to d[k-1])

Assume k = 3

The couple would have saved for 2 item

$Savings = d[1] + d[2]$

$Savings = 30 +10$

$Savings = 40$

The saved amount will then be added to the kth item in list a i.e. a[k](in this case k = 3) in order to buy b[k]

Using the assumed value of k

$a[k] = a[3]$

$a[3] = 160$

$b[3] = 165$

Add the saved amount (40) to a[3]

$New\ Amount = 40 + 160$

$New\ Amount = 200$

This new amount can then be used to buy b[3] i.e. 165, then they save the change for subsequent items

8 0

3 years ago

Input an int between 0 and 100 and print the numbers between it and 100, including the number itself and the number 100. If the

Murrr4er [49]

import java.util.Scanner;

public class JavaApplication42 {

public static void main(String[] args) {

Scanner scan = new Scanner(System.in);

int count = 0;

System.out.println("Enter an integer between 0 and 100");

int num = scan.nextInt();

if (num <= 0 || num >= 100){

System.out.println("error");

}

else{

while(num <= 100){

if (count == 20){

System.out.println("");

count = 0;

}

else{

System.out.print(num+" ");

count++;

num++;

}

I hope this helps!

6 0

3 years ago

1.5 Code Practice: Question 1

Jobisdone [24]

What’s the question?
Always remember to add any reasonable information for someone to help or answer!!

Have a good rest of your day.

6 0

3 years ago