The answer is D :) II hope that this helps and if you need a bigger description I can help
Answer:
70%
Step-by-step explanation:
I'm sorry but I don't really know how to explain it other than 70% of 30 is 21 so that means that 30% of the students turned their essay in on time.
(sorry for not being able to explain it but I hope it helped)
What we have so far:
Kinetic energy = 0. The reason behind that is because the beam is not moving at a height of 40m.
Gavity, g = 9.8m/s²
Height = 40m
Potential energy = mgh; this is equal to 0 because m, stands for mass and in this problem, we do not have a value for the mass of the beam. Hence, 0 x 9.8m/s² x 40m = 0. Potential energy = 0.
Solution:
We will use the equation of Total energy:
TE = potential energy + kinetic energy
TE = 0 + 0
∴ TE = 0
The answer is: Assuming no air resistance, the total energy of the beam as it hits the ground is 0.
Answer:
Step-by-step explanation:
Part A:
3x+12+7x+88=180
10x+100=180
10×=80
X=8
Part B:
m<RPS=3x+12
(3*8)+12
=36
