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MakcuM [25]
4 years ago
12

Which inequality is true if p= 3.4?

Mathematics
1 answer:
BigorU [14]4 years ago
7 0

Answer:

None of the equations are true for p = 3.4

Step-by-step explanation:

In order for the inequality to be valid we need to apply the value for p and check wether or not it is true. We gonna do for each of the following:

A. 3p < 10.2

3*3.4 < 10.2

10.2 < 10.2

Not true, since the left side is equal to the right side and not less.

B. 13.6 < 3.9p

13.6 < 3.9*3.4

13.6 < 13.26

Not true since 13.6 is greater than 13.26

C. 5p > 17.1

5*3.4 > 17.1

17 > 17.1

Not true since 17 is less than 17.1

D. 8.5 > 2.5p

8.5 > 2.5*3.4

8.5 > 8.5

Not true since the left side is equal to the right side.

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Suppose that y varies inversely with x and y = 3 when x=10 find y when x=5
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Answer:

y=1.5

Step-by-step explanation:

if (y = 3) is  (x = 10) and (y = ?) is (x = 5) we see that x is half of the first equation in the second. This means we divide both variables in the first equation by half to get the second. [(x = 10) / 2 = (x = 5)] therefor, [(y = 3) / 2 = (y = 1.5)]. Making your answer 1.5.

Hope this helps :)

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You are going to visit your aunt who lives 25 miles away . You have already traveled 7.7 miles. What percentage of the trip is s
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Answer:

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Step-by-step explanation:

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Answer:

Following are the responses to the given points:

Step-by-step explanation:

Dilation implies the triangle \Delta XYZ stretched through the factor "2".  

m\angle Y = m\angle C = 90^{\circ} \leftarrow given \\\\  

right triangles:

\Delta  XYZ and \Delta  ACB \\\\\angle X \cong \angle A \leftarrow given\\\\

complementary angles:  

\angle X \ and\  \angle Z

m\angle Z = 90^{\circ} - m\angle X \\\\

complementary angles:

\angle A \ and\  \angle B

m\angle B = 90^{\circ} - m\angle A \\\\\therefore \\\\ \angle Z \cong \angle B \\\\\Delta  XYZ \sim  \Delta ACB \\\\

Same triangles: proportional side are corresponding, congruence angles are respective.

\sin \angle X = \frac{5}{5.59} \leftarrow given \\\\\sin\angle X = \frac{YZ}{XY} \\\\YZ = 5 (units) \rightarrow leg in \Delta XYZ \\\\XZ = 5.59 (units) \rightarrow hypotenuse \ in\  \Delta XYZ\\\\

Calculating the length of leg XY:

XY = \sqrt{((5.59)^2 - 52)} \cong 2.4996 (units)\\\\\frac{CB}{YZ} = 2 \leftarrow given \\\\CD = 2YZ = 2 \times 5 = 10 \ (units)\\\\\frac{AC}{XY} = 2 \leftarrow  \ given\\\\AC = 2XY \cong 2 \times  2.4996 \cong 4.999\  (units)\\\\

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