Find the measure of z.

Evaluate 5! 4! ____ 7! 2! Simple as much as possible

shepuryov [24]

The value of the factorial is 5!4!/7!2! = 2/7

<h3>What is factorial?</h3>

The product of all positive integers less than or equal to a given positive integer and denoted by that integer and an exclamation point.

Given:

5!4!/7!2!

= 5!* 4*3*2!/7*6*5!*2!

=4*3/7*6

=12/42

=4/14

=2/7

Hence, 5!4!/7!2! = 2/7.

Learn more about factorial here:

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8 0

1 year ago

The triangles are similar. What is the value of x? Enter your answer in the boX.

matrenka [14]

6x+28=25

or,x=-1/2

Step-by-step explanation:

corresponding sides i think so

6 0

3 years ago

Read 2 more answers

Lionfish are considered an invasive species, with an annual growth rate of 67%. A scientist estimates there are 8,000 lionfish i

natita [175]

Answer:

There would be 173,535 lionfish after 6 years.

Step-by-step explanation:

Since lionfish are considered an invasive species, with an annual growth rate of 67%, ya scientist estimates there are 8,000 lionfish in a certain bay after the first year, A) to write the explicit equation for f (n) that represents the number of lionfish in the bay after n years; B) determine how many lionfish will be in the bay after 6 years; and C) if scientists remove 1,200 fish per year from the bay after the first year, determine what is the recursive equation for f (n); the following calculations must be performed:

A)

8000 x 1.67 ^ n = f

B)

8000 x 1.67 ^ 6 = X

8000 x 21.691961596369 = X

173,535.692770952 = X

C)

(8000 - 1200 x 1 ^ n) x 1.67 ^ n = f

Therefore, there would be 173,535 lionfish after 6 years.

5 0

2 years ago

1. The national mean (μ) IQ score from an IQ test is 100 with a standard deviation (s) of 15. The dean of a college wants to kno

Nat2105 [25]

Answer:

We conclude that the mean IQ of her students is different from the national average.

Step-by-step explanation:

We are given that the national mean (μ) IQ score from an IQ test is 100 with a standard deviation (s) of 15.

The dean of a college want to test whether the mean IQ of her students is different from the national average. For this, she administers IQ tests to her 144 students and calculates a mean score of 113

Let, Null Hypothesis, $H_0$ : $\mu$ = 100 {means that the mean IQ of her students is same as of national average}

Alternate Hypothesis, $H_1$ : $\mu\neq$ 100 {means that the mean IQ of her students is different from the national average}

(a) The test statistics that will be used here is One sample z-test statistics;

T.S. = $\frac{Xbar-\mu}{\frac{s}{\sqrt{n} } }$ ~ N(0,1)

where, Xbar = sample mean score = 113

s = population standard deviation = 15

n = sample of students = 144

So, test statistics = $\frac{113-100}{\frac{15}{\sqrt{144} } }$

= 10.4

Now, at 0.05 significance level, the z table gives critical value of 1.96. Since our test statistics is more than the critical value of z which means our test statistics will fall in the rejection region and we have sufficient evidence to reject our null hypothesis.

Therefore, we conclude that the mean IQ of her students is different from the national average.

3 0

3 years ago

The probability that a given urine sample analyzed in a pathology lab contains protein is 0.73 (event A). The probability that t

Ostrovityanka [42]

The right answer for the question that is being asked and shown above is that: "e.Events A and B are dependent because P(A|B) = P(A)." The probability that a sample contains protein, given that albumin is detected, is 1. The statement that is true is this events A and B are dependent because P(A|B) = P(A).

3 0

3 years ago