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german
4 years ago
6

What is 9bc - 6b written in factored form?​

Mathematics
1 answer:
sattari [20]4 years ago
3 0

Answer:

<h2>9bc - 6b = 3b(3c - 2)</h2>

Step-by-step explanation:

9bc=(3b)(3c)\\\\6b=(3b)(2)\\\\\text{Distributive property:}\ a(b+c)=ab+ac\\\\9bc-6b=(3b)(3c)-(3b)(2)=(3b)(3c-2)

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Anyone help me. ....​
weeeeeb [17]

Answer:

see explanation

Step-by-step explanation:

Using the rules of exponents

All the exponents inside the parenthesis are multiplied by the exponent outside the parenthesis.

Then

\frac{m^{-7}n^{14}  }{m^{-25}n^{40}  } ÷ \frac{m^{-21}n^{42}  }{m^{-25}n^{40}  }

[ Using the rule \frac{a^{m} }{a^{n} } = a^{(m-n)} ]

= m^{(-7-14)} n^{(14-(-28)} ÷ m^{(-15-10)} n^{(25-(-15)}

= m^{-21} n^{14+28} ÷ m^{-25} n^{25+15}

= \frac{m^{-21}n^{42}  }{m^{-25}n^{40}  }

= m^{(-21-(-25))} n^{(42-40)}

= m^{(-21+25)} n²

= m^{4} n² = m^{x} n^{y} , so x = 4 and y = 2

Then

m^{x-2y} = m^{4-2(2)} = m^{4-4} = m^{0} = 1 ← as required

6 0
3 years ago
$11.20 is 30% of what number
amm1812
The answer is $1120.00.
8 0
3 years ago
How do i check an equation for extraneous solutions?
Marina86 [1]
Example:

\sqrt x(x+1)=0

This suggests two solutions, x=0 and x=-1.

However, upon plugging these solutions back into the equation, you get

\sqrt0(0+1)=0(1)=0

which checks out, but

\sqrt{-1}(1-1)=0

does not because \sqrt x is defined only for x\ge0 (assuming you're looking for real solutions only). So, we call x=-1 an extraneous solution, and the complete solution set (over the real numbers) is x=0.
7 0
3 years ago
Read 2 more answers
#46 I have tried several times
natita [175]
Let x be the number of tickets sold
Cost of x tickets = 32.5.x
Cost of convenience  = 3.3.x
Process charges (for ONE ORDER, whatever the number of tickets) = $5.90

Hence:
$32.5(x)  +  $3.3(x)  +  $5.90 = $220.70


$35.8(x) = $220.90-$5.90

$35.8(x) = $214.8
 
And x = 214.8/35.8 = 6 tickets

4 0
4 years ago
6 decigrams = milligrams
malfutka [58]
1 decigram = 100 milligrams

6 decigrams = 600 milligrams
6 0
3 years ago
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