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3 years ago

Solve the equation x2-16x+54=0

Mathematics

2 answers:

kari74 [83]3 years ago

7 0

Answer:

x1 = 8+√10, x2 = 8 -√10

Step-by-step explanation:

x² - 16x + 54 = 0

$x = \frac{-b +/-\sqrt{b^{2} -4ac} }{2a} \\x = \frac{-(-16)+/-\sqrt{(-16)^{2} -4*1*54} }{2*1} \\\\\\x = \frac{16+/-\sqrt{(40)} }{2*1} = 8+/-\sqrt{10} \\\\x_{1} = 8+\sqrt{10}\\\\x_{2} =8-\sqrt{10}$

Vladimir [108]3 years ago

3 0

Answer:

x1 = 8+√10, x2 = 8 -√10

Step-by-step explanation:

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Answer:

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Step-by-step explanation:

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