Answer:
The last graph.
Step-by-step explanation:
The last graph because it shows the continum of time, and it shows him getting closer to the school (decrease in distance), then it shows him picking up Janet (staying constant), then it shows him going back home to grab his books (increase in distance), all as time goes on.
3/5a = 1/4....multiply both sides by 5/3, cancelling out the 3/5 on the left
a = 1/4 * 5/3
a = 5/12
1-3 are about trigonometric ratios (SOH CAH TOA). 4, 5 are about the Law of Cosines, and 6 uses the Law of Sines.
1. Sin = Opposite/Hypotenuse
x = 10*sin(40°) ≈ 6.428
2. Sin = Opposite/Hypotenuse
x = arcsin(7/12) ≈ 35.69°
3. Tan = Opposite/Adjacent
x = 18/tan(52°) ≈ 14.063
4. b^2 = a^2 +c^2 -2ac*cos(B)
B = arccos((a^2 +c^2 -b^2)/(2ac)) = arccos((7^2 +13^2 -8^2)/(2*7*13))
B = arccos(11/13) ≈32.20°
5. Same formula.
x = √(a^2 +c^2 -2ab*cos(B)) = √(157-132cos(42°)) ≈ 7.675
6. The ratio of side lengths is the same as the ratio of the sines of the opposite angles.
6/10 = sin(x)/sin(100°)
x = arcsin((6/10)*sin(100°)) ≈ 36.22°
Please brainless if it’s wrong please message me
Hey, Are you in K12/TXVA too? We might be in the same class and could help each other out. Either way, here's the answer:
f(x) = x^5
g(x) = sqrt(x)
h(x) = 2x
You place h(x) in g(x) and then that inside of f(x).