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valina [46]
3 years ago
11

For a gene that determines wing color in butterflies, there are three possible genotypes: BB (blue wings), bb (white wings), and

Bb (white wings with blue blotches). A sample of 100 butterflies was collected, and the following was observed:
Wing Color Number of Butterflies
blue 60
white with blue blotches 30
white 10


What is the frequency of the Bb genotype in this population if it is in Hardy-Weinberg Equilibrium?
Biology
1 answer:
Oduvanchick [21]3 years ago
3 0

Answer: The frequency of the b allele is calculated as follows: since there are 2 alleles in each organism, total number of genes is 200. The number of white alleles is 10*2+30 (since there are 2 copies of the alleles in white organisms and 1 copy of the b allele in the white wings with blue blotches). So the total number of white alleles is 20+30=50 white alleles. The frequency of the white allele is then 0.25. So the frequency of the blue allele is 1-0.25=0.75. Since heterozygous term is 2*p*q, the frequency of the Bb genotype is 2*0.25*0.75=0.375. Hope that helped!

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Answer:

(a) 1/2; (b) no

Explanation:

Glucose-6-phosphate dehydrogenase deficiency (G6PD) is an X-linked recessive disorder and the woman's father was diseased so it means that woman is a carrier of the allele but has normal phenotype. It means that she will have XXᵇ genotype.

In contrast to this, her husband is diseased so his genotype will be XᵇY.

The Punnett square diagram related to the cross is attached.

(a) Proportion of their sons expected to be G6PD is 1/2:

They both may give birth to 4 progeny with genotypes XXᵇ, XᵇXᵇ, XY and XᵇY. It means they both may have 2 sons out of which one with genotype XᵇY will be diseased while the one with genotype XY will be healthy. So the proportion of their sons having G6PD is 1/2 or 50%.

(b) If the husband were G6PD deficient, the answer will not change.

The reason behind this is that this disease is caused by an allele located in X chromosome. But father contributes only Y chromosome to his son not X chromosome. The X chromosome will affect the genotype of his daughter not son that is why answer will not change. It means they will still have 1/2 of their sons diseased.  

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