Answer:
ATP, Mitochondria, Cellular respiration.
Explanation:
The Krebs cycle of, cellular respiration, in the mitochondria results to the an accumulation of protons in the inter-membrane space of the organelle. This proton motive force is harnessed in the electron transport chain by ATP synthase to generate ATPs.
The term Neurotransmitter describes the chemical substances that make it possible for messages to cross from the synapse of a neuron to the target receptor.
<h3>What are Neurotransmitters?</h3>
- Neurotransmitters are endogenous chemicals that allow neurons to communicate with each other throughout the body.
- Chemical synaptic transmission is primarily through the release of neurotransmitters from presynaptic neural cells to postsynaptic receptors.
- There are a number of neurotransmitters used by the body for different functions, including acetylcholine, norepinephrine, glutamate, GABA, glycine, dopamine, and serotonin.
- Glutamate is the principal excitatory neurotransmitter used in the brain.
- GABA and Glycine serve as the major inhibitory neurotransmitters.
To learn more about Neurotransmitters,
brainly.com/question/1980965
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The answer is D . Pressure causes water and dissolved substances to filter though capillary walls of the glomerulus .
Answer:
cumulative dilution = 0.000001
Explanation:
A serial dilution is a stepwise kind of dilution repeated a certain number of times, in which the concentration reduces exponentially each time.
The cumulative dilution is the final dilution gotten depending on the number of times dilution has been done and the dilution factor. The formula is given as:
Cumulative dilution = (F)ⁿ
where:
F = dilution factor = 0.1
n = number of serial dilutions = 6
∴ cumulative dilution = (0.1)⁶ = 0.000001
Answer No 1:
The set up of the punnet square is shown in the attached diagram. As the alleles assort independently hence the gametes formed will be OT,Ot,OT,Ot and OT,Ot,oT,ot. These will be the outcomes of the possible gametes formed. When these gametes are cross bred, the results are shown in the diagram attached.
Answer No 2:
The outcomes of each possible genotype are:
OOTT = 2/16
OOTt = 4/16
OOtt = 2/16
Oott = 2/16
OoTT = 2/16
OoTt = 4/16
Answer No 3:
The likelihood of each possible offspring phenotype is:
Orange petals with tall stem and orange petals with small stems present in ratio 12:4 i.e. 3:1.
