Answer:
25.95 quarters which is about 6.5 years
Step-by-step explanation:
Answer: 84 in
Step-by-step explanation:
The length down is the same as the top one.
Answer:
The answer is below
Step-by-step explanation:
Find the dimensions of the rectangle of maximum area with sides parallel to the coordinate axes that can be inscribed in the ellipse 4x² + 16y² = 16
Solution:
Given that the ellipse has the equation: 4x² + 16y² = 16
let us make x the subject of the formula, hence:
4x² + 16y² = 16
4x² = 16 - 16y²
Dividing through by 4:
x² = (16 - 16y²)/4
x² = 4 - 4y²
Taking square root of both sides:
The points of the rectangle vertices is at (x,y), (-x,y), (x,-y), (-x,-y). Hence the rectangle has length and width of 2x and 2y.
The area of a rectangle inscribed inside an ellipse is given by:
Area (A) = 4xy
A = 4xy
Therefore the length = 2x = 2√2, the width = 2y = 2/√2
Answer:
Step-by-step explanation:
Subtract 1 from both sides.
Divide both sides by 7.
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