1. At 7 a.m., the science classroom had a temperature of 68°F. By 3 p.m., the temperature had

In the molecule on the left, areas that have a partial negative charge are pink and areas that have a partial positive charge ar

Gwar [14]

Answer : Option C) An induced dipole will be produced in the molecule on the right.

Explanation : As per the given information there is a polar molecule which is placed on the left side which has partial positive charge at one end and on other end has partial negative charge which shows that it has a dipole in it. It tries to induce the non-polar molecule which is at right side. So, there will be an induce dipole interaction between both when they are placed closer to each other.

3 0

3 years ago

Read 2 more answers

Calculate the ph of a solution prepared by dilution 3.0 ml of 2.5 m hcl to a final volume of 100 ml with h2o.

dexar [7]

The pH of the solution after dilution is 1.125.

HCl is hydrochloric acid. It is known by the name muriatic acid. It is among the strong acids. It has a pungent smell and is colorless. It has a molar mass of 36.4 g/mol. It's a common reagent used in pharmaceutical industries. It is also used in other industries such as textile, rubber, and metal.

The volume of HCl added to the solution = 3.0 ml

The molar concentration of HCl = 2.5 M

Let the molar concentration of the solution after dilution is x.

The volume of the diluted solution = 100 ml.

The molar concentration of the solution after dilution is,

$M _{1} V _{2} = M_{2} V _{2}$

$M_{2} = \frac{ M _{1} V _{2}}{V _{2} }$

$M_{2} = \frac{2.5 \times 3}{100}$

$= 0.075 \: M$

Thus, the molar concentration of the solution after dilution is 0.075 M.

The pH of the solution after the dilution is,

$[HCl] = [H ^{ + } ] = 0.075 \: M$

$pH = - log [H ^{ + } ]$

$pH = - log(0.075)$

$pH = 1.125$

Therefore, the pH of the solution after dilution is 1.125.

To know more about hydrochloric acid, refer to the below link:

brainly.com/question/3637432

#SPJ4

3 0

2 years ago

Aqueous hydrobromic acid reacts with solid sodium hydroxide to produce aqueous sodium bromide and liquid water . What is the the

natima [27]

Mass of water produced is equal to 7.2 grams.

The reactants are reacting according to the following equation:

HBr + NaOH = NaBr + H2O

1 mole of HBr requires 1 mole of NaOH to be totally transformed into NaBr and water.

Now, let us calculate the amounts of HBr and NaOH in mols:

m(HBr) = 67.2g

m(NaOH) = 16g

M(HBr) = 80.9g/mol

M(NaOH) = 40g/mol

Following the simple relation

n(moles) = m(grams)/M(g/mol)

n(HBr) = 67.2g/(80.9g/mol)

n(NaOH) = 16g/(40g/mol)

n(H2O) = n(NaOH) = 0.40 mol, which is:

m(H2O) = n(H2O) x M(H2O)

0.40mol∗18g/mol=7.2g

Finally, the mass of water produced is equal to 7.2 grams.

Learn more about Hydrobromic acid here:

brainly.com/question/21544156

#SPJ4

8 0

2 years ago

The specific heat of copper is 0.092 cal/g °C. If a 590 g copper pan is heated from a temperature of 25 °C to 180 °C, how many c

Lerok [7]

$Q=cm \Delta T\\\\
c=0,092\frac{cal}{g^{o}C}\\
m=590g\\
\Delta T=180^{o}C-25^{o}C=155^{o}C\\\\
Q=0,092\frac{cal}{g^{o}C}*590g*155^{o}C=8413,4cal$

8 0

3 years ago

How many moles are present in 4.50 L of fluorine gas (F2) at Standard Temperature and<br> Pressure?

Delicious77 [7]

Answer:

4.50 L gas of fluorine at STP contain 0.2 moles.

Explanation:

Given data:

Volume of gas = 4.50 L

Number of moles F₂ gas = ?

Temperature of gas = standard = 273.15 K

Pressure of gas = standard = 1 atm

Explanation:

Formula:

PV = nRT

P= Pressure

V = volume

n = number of moles

R = general gas constant = 0.0821 atm.L/ mol.K

T = temperature in kelvin

Now we will put the values in formula.

1 atm × 4.50 L = n × 0.0821 atm.L/ mol.K × 273.15 K

4.50 atm.L = n × 22.43 atm.L/ mol.

n = 4.50 atm.L / 22.43 atm.L/ mol.

n = 0.2 mol

4.50 L gas of fluorine at STP contain 0.2 moles.

4 0

3 years ago