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Brilliant_brown [7]
3 years ago
8

The specific heat of copper is 0.092 cal/g °C. If a 590 g copper pan is heated from a temperature of 25 °C to 180 °C, how many c

alories of heat energy will the copper pan absorb?
Chemistry
1 answer:
Lerok [7]3 years ago
8 0
Q=cm \Delta T\\\\
c=0,092\frac{cal}{g^{o}C}\\
m=590g\\
\Delta T=180^{o}C-25^{o}C=155^{o}C\\\\
Q=0,092\frac{cal}{g^{o}C}*590g*155^{o}C=8413,4cal
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