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Stels [109]
2 years ago
10

Aqueous hydrobromic acid reacts with solid sodium hydroxide to produce aqueous sodium bromide and liquid water . What is the the

oretical yield of water formed from the reaction of of hydrobromic acid and of sodium hydroxide
Chemistry
1 answer:
natima [27]2 years ago
8 0

Mass of water produced is equal to 7.2 grams.

The reactants are reacting according to the following equation:

HBr + NaOH = NaBr + H2O

1 mole of HBr requires 1 mole of NaOH to be totally transformed into NaBr and water.

Now, let us calculate the amounts of HBr and NaOH in mols:

m(HBr) = 67.2g

m(NaOH) = 16g

M(HBr) = 80.9g/mol

M(NaOH) = 40g/mol

Following the simple relation

n(moles) = m(grams)/M(g/mol)

n(HBr) = 67.2g/(80.9g/mol)

n(NaOH) = 16g/(40g/mol)

n(H2O) = n(NaOH) = 0.40 mol, which is:

m(H2O) = n(H2O) x M(H2O)

0.40mol∗18g/mol=7.2g

Finally, the mass of water produced is equal to 7.2 grams.

Learn more about Hydrobromic acid here:

brainly.com/question/21544156

#SPJ4

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leonid [27]

Answer:

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Explanation:

Chemical equation:

NO₂ + NO₃ → N₂O₅

Balanced chemical  equation:

NO₂ + NO₃ → N₂O₅

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This is the simple synthesis reaction in which two substance combine to form a new substance.

Synthesis reaction:

It is the reaction in which two or more simple substance react to give one or more complex product.

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3 years ago
Wet steam at 1100 kPa expands at constant enthalpy (as in a throttling process) to 101.33 kPa, where its temperature is 105°C. W
nikklg [1K]

Answer:

There are 3 steps of this problem.

Explanation:

Step 1.

Wet steam at 1100 kPa expands at constant enthalpy to 101.33 kPa, where its temperature is 105°C.

Step 2.

Enthalpy of saturated liquid Haq = 781.124 J/g

Enthalpy of saturated vapour Hvap = 2779.7 J/g

Enthalpy of steam at 101.33 kPa and 105°C is H2= 2686.1 J/g

Step 3.

In constant enthalpy process, H1=H2 which means inlet enthalpy is equal to outlet enthalpy

So, H1=H2

     H2= (1-x)Haq+XHvap.........1

    Putting the values in 1

    2686.1(J/g) = {(1-x)x 781.124(J/g)} + {X x 2779.7 (J/g)}

                        = 781.124 (J/g) - x781.124 (J/g) = x2779.7 (J/g)

1904.976 (J/g) = x1998.576 (J/g)

                     x = 1904.976 (J/g)/1998.576 (J/g)

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So, the quality of the wet steam is 0.953

                   

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