Mass of water produced is equal to 7.2 grams.
The reactants are reacting according to the following equation:
HBr + NaOH = NaBr + H2O
1 mole of HBr requires 1 mole of NaOH to be totally transformed into NaBr and water.
Now, let us calculate the amounts of HBr and NaOH in mols:
m(HBr) = 67.2g
m(NaOH) = 16g
M(HBr) = 80.9g/mol
M(NaOH) = 40g/mol
Following the simple relation
n(moles) = m(grams)/M(g/mol)
n(HBr) = 67.2g/(80.9g/mol)
n(NaOH) = 16g/(40g/mol)
n(H2O) = n(NaOH) = 0.40 mol, which is:
m(H2O) = n(H2O) x M(H2O)
0.40mol∗18g/mol=7.2g
Finally, the mass of water produced is equal to 7.2 grams.
Learn more about Hydrobromic acid here:
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