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son4ous [18]
3 years ago
11

An elastic band with a spring constant of 62 N/m is extended by 0.15 m. What is the force applied to the rubber band?

Chemistry
2 answers:
Phoenix [80]3 years ago
7 0

the force applied to the rubber band is -9.3N

Explanation:

Ymorist [56]3 years ago
4 0

Answer:

the force applied to the rubber band is -9.3N

Explanation:

The computation of the force applied to the rubber band is shown below;

We know that

Force in newtons = Spring constant × amount of extension

F = -k × x

where

-k = 62 N/m

And, x = 0.15m

So, the force applied is

= -62N/m × 0.15m

= -9.3N

hence, the force applied to the rubber band is -9.3N

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Explanation:

  Process

1.- Multiply Equation 1 by 2

           2C(coal) + 2H₂O   ⇒   2CO (g) + 2H₂      ΔH rxn = 259.4 kJ

2.- Sum equation 2

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Result

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Simplification

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3.- Sum equation 3

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Result

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Simplification

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