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Paul [167]
3 years ago
13

The The geometrics decide to play a concert in the gym. The gym measures 100 feet long by 60 feet wide by 30 feet tall. The band

asks the stage crew how loud they can play in the gym. After some experimenting, the stage crew calculates that the band can turn up the amplifier volume one notch for every 18,000 ft.³. So how loud can the geometrics have their amplifiers in this room?
Mathematics
1 answer:
hammer [34]3 years ago
7 0
So what you do is multiply 60, 30, and 100 together to get 180,000. Then divide 180,000 by 18,000 (simplify it to 180 ÷ 18) and the answer is 10. So they could turn it up 10 notches.
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Write the column B the reverse pertuna
sweet-ann [11.9K]

Answer:

it is 2

Step-by-step explanation:

i think it is

8 0
2 years ago
The length of a rectangle is twice the width. If the perimeter of the rectangle is 60 units, find the area of the garden.​
AlexFokin [52]
Perimeter = (length+width) x 2


Let w units be the width of the rectangle.

Length of the rectangle = 2w

Perimeter:
(2w+w) x 2 = 60

(3w)2 = 60

6w = 60

w = 10


Area:
2(10) x 10

= 20 x 10

= 200 units

4 0
2 years ago
X and y are normal random variables with e(x) = 2, v(x) = 5, e(y) = 6, v(y) = 8 and cov(x,y)=2. determine the following: e(3x 2y
andriy [413]

The result for the given normal random variables are as follows;

a. E(3X + 2Y) = 18

b. V(3X + 2Y) = 77

c. P(3X + 2Y < 18) = 0.5

d. P(3X + 2Y < 28) = 0.8729

<h3>What is normal random variables?</h3>

Any normally distributed random variable having mean = 0 and standard deviation = 1 is referred to as a standard normal random variable. The letter Z will always be used to represent it.

Now, according to the question;

The given normal random variables are;

E(X) = 2, V(X) = 5, E(Y) = 6, and V(Y) = 8.

Part a.

Consider E(3X + 2Y)

\begin{aligned}E(3 X+2 Y) &=3 E(X)+2 E(Y) \\&=(3) (2)+(2)(6 )\\&=18\end{aligned}

Part b.

Consider V(3X + 2Y)

\begin{aligned}V(3 X+2 Y) &=3^{2} V(X)+2^{2} V(Y) \\&=(9)(5)+(4)(8) \\&=77\end{aligned}

Part c.

Consider P(3X + 2Y < 18)

A normal random variable is also linear combination of two independent normal random variables.

3 X+2 Y \sim N(18,77)

Thus,

P(3 X+2 Y < 18)=0.5

Part d.

Consider P(3X + 2Y < 28)

Z=\frac{(3 X+2 Y-18)}{\sqrt{77}}

\begin{aligned} P(3X + 2Y < 28)&=P\left(\frac{3 X+2 Y-18}{\sqrt{77}} < \frac{28-18}{\sqrt{77}}\right) \\&=P(Z < 1.14) \\&=0.8729\end{aligned}

Therefore, the values for the given normal random variables are found.

To know more about the normal random variables, here

brainly.com/question/23836881

#SPJ4

The correct question is-

X and Y are independent, normal random variables with E(X) = 2, V(X) = 5, E(Y) = 6, and V(Y) = 8. Determine the following:

a. E(3X + 2Y)

b. V(3X + 2Y)

c. P(3X + 2Y < 18)

d. P(3X + 2Y < 28)

8 0
2 years ago
I would appreciate if someone could answer this :)
Gnom [1K]

Answer:

x = 8

y = 6

Step-by-step explanation:

Recall that one of the properties of a parallelogram is that the diagonals bisect each other, which means they divide each other into equal segments.

Therefore,

LP = PN

x = y + 2 (eqn. 1)

PM = KP

2x - 8 = y + 10 (eqn. 2)

Substitute x = y + 2 into eqn. 2 to find y

Thus:

2(y + 2) = y + 10

2y + 4 = y + 10

Take like terms

2y - y = -4 + 10

y = 6

Substitute y = 6 into eqn. 1 to find x:

x = y + 2 (eqn. 1)

x = 6 + 2

x = 8

7 0
3 years ago
Find the product 7 x 300 = hundreds
Evgesh-ka [11]
7 x 300 = 2,100 hope i helped and there are 21 hundreds in 2,100
4 0
3 years ago
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