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Julli [10]
3 years ago
10

What is the difference between a continuous spectrum and a dis?

Physics
1 answer:
madam [21]3 years ago
7 0
<span>A continuous spectrum is one where the light emitted goes along the entire spectrum. A line spectrum is one that only emits a few frequencies. </span>
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Define principal focus of concave mirror.Where should we place a candle in front of a concave mirror to get an enlarged,erect im
Mars2501 [29]

Answer

The image formed by a concave mirror will be virtual, erect and magnified when the object is placed only between the pole and the principal focus of the mirror.

Hope it helped u if yes mark me brainliest!

Tysm!

3 0
4 years ago
A 1.50-m cylinder of radius 1.10 cm is made of a complicated mixture of materials. Its resistivity depends on the distance x fro
MArishka [77]

Answer:

Resistance = 3.35*10^{-4} Ω

Explanation:

Since resistance R = ρ\frac{L}{A}

whereas \rho(x) = a + bx^2

resistivity is given for two ends. At the left end resistivity is 2.25* 10^{-8} whereas x at the left end will be 0 as distance is zero. Thus

2.25*10^{-8} = a + b(0)^2\\ 2.25*10^{-8} = a + 0 \\2.25*10^{-8} = a

At the right end x will be equal to the length of the rod, so x = 1.50\\8.50*10^{-8} = (2.25*10^{-8}) + ( b* (1.50)^2 )\\8.50*10^{-8} - (2.25*10^{-8}) = b*2.25\\\frac{6.25*10^{-8}}{2.25}  = b\\b = 2.77 *10^{-8}

Thus resistance will be R = ρ\frac{L}{A}

where A = π r^2

so,

R = \frac{8.50*10^{-8} * 1.50}{3.14*(1.10*10^{-2})^2} \\R=3.35 * 10 ^{-4}

6 0
3 years ago
11 Design Imagine that a scientistdiscovered a way to make africtionless surface. What wouldbe some useful applications forthis
m_a_m_a [10]

Answer:

You could move something across the Earth with a little push. It would make fuel really efficient on those pathways. You could make a floor that is impossible to walk on. Everybody would just fall without traction.

Explanation:

3 0
3 years ago
A vessel is filled with a liquid of density 1900 kg/m3 . There are two holes (one above the other) in the side of the vessel. Li
FromTheMoon [43]

Answer:

110 meters is the distance where they will intersect

Explanation:

given,

liquid density = 1900 kg/m³

distance of upper hole = 19 m

distance of lower hole = 117 m

acceleration due to gravity  = 9.8 m/s²

the speed at each point

v = \sqrt{2gh}  

for upper hole  v = \sqrt{2\times 9.8 \times 19}  

                         v  = 19.29 m/s

lower hole    v = \sqrt{2\times 9.8 \times 117}  

                          v = 47.88 m/s

The path for each is parabolic

x = v t

y = \dfrac{1}{2}gt^2  

y = \dfrac{1}{2}g(\dfrac{x}{v})^2  

y = \dfrac{gx^2}{2v^2}  

we get

upper hole

y = \dfrac{9.8\times x^2}{2\times 19.29^2}= 0.0132 x^2  lower hole

y= \dfrac{9.8\times x^2}{2\times 47.88^2}=0.00214x^2  y for upper hole = 80 + y for lower hole

0.0132 x^2= 98 + 0.00214 x^2

0.0082 x^2 = 98

x = 109.32 meters

110 meters is the distance where they will intersect

4 0
3 years ago
A canon is tilled back 30.0 degrees and shoots a cannon ball at 155 m/s. What is the
Umnica [9.8K]

Answer:

= \frac{(115^2)(\sin 30)^2}{2\times 9,8} \\\\= 168.7m

Therefore, highest point that the cannon ball reaches is 168.7m

Explanation:

the cannon is fired at an angle 30 o to the horizonatal with a speed of 155 m/s

highest point that the cannon ball reaches?

H_{max}=\frac{V^2\sin ^2 \theta}{2g}

g = 9.8m/s2

= \frac{(115^2)(\sin 30)^2}{2\times 9,8} \\\\= 168.7m

Therefore, highest point that the cannon ball reaches is 168.7m

6 0
4 years ago
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