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AlexFokin [52]
3 years ago
14

A shopper in a supermarket pushes a loaded 31 kg cart with a horizontal force of 12 N. The acceleration of gravity is 9.81 m/s 2

. a) Disregarding friction, how far will the cart move in 4.2 s, starting from rest? Answer in units of m.
Physics
1 answer:
rosijanka [135]3 years ago
3 0

Answer:

3.41334 m

Explanation:

t = Time taken

u = Initial velocity

v = Final velocity

s = Displacement

a = Acceleration

m = Mass

Force

F=ma\\\Rightarrow a=\frac{F}{m}\\\Rightarrow a=\frac{12}{31}\\\Rightarrow a=0.387\ m/s^2

Acceleration of the cart is 0.387 m/s²

s=ut+\frac{1}{2}at^2\\\Rightarrow s=0\times 4.2+\frac{1}{2}\times 0.387\times 4.2^2\\\Rightarrow s=3.41334\ m

The cart will move 3.41334 m in 4.2 seconds

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A shell is fired from the ground with an initial speed of 1.74 ✕ 103 m/s at an initial angle of 58° to the horizontal.
ValentinkaMS [17]

Answer:

a) horizontal range s=277671.77 m

b) time the shell is in motion 301.143 s

Explanation:

Is a parabolic movement so the velocity have two components:

v = 1.74 x 10^{3}  ( \frac{m}{s} )

\alpha = 58°

v_{y} =v*Sen (\alpha )\\v_{x} =v*Cos (\alpha )

v_{y} =1740*Sen (58 )\\v_{x} =1740*Cos (58)

v_{y} = 1475.603 \frac{m}{s}\\v_{x} = 922.059 \frac{m}{s}\\

t= \frac{2*v_{y} }{g}

t= \frac{2*1475.603 }{9.8}

t= 301.143 s

v= \frac{s}{t} \\s= v_{x}*t

s= 922.059 \frac{m}{s} * 301.143 s

s = 277671.77 m

4 0
4 years ago
How does a bicycle rider's energy of motion changes as the gain speed while riding down a hill?
kaheart [24]
It is b. It gains momentum when going down. Think of it like a sled. When you go up the hill, it goes slower, but when you go down the hill, you gain speed(momentum) and it increases
8 0
4 years ago
What is surface tension and what phase of matter creates it?
hram777 [196]

Answer:

The property of the surface of a liquid that allows it to resist an external force, due to the cohesive nature of its molecules.The cohesive forces between liquid molecules are responsible for the phenomenon known as surface tension.

If i'm wrong correct me.

4 0
3 years ago
Iron filings scattered around a magnet will be most strongly drawn toward the _____.
victus00 [196]
<span>The answer is towards <span>the poles. This is because, at the poles of the magnet, the magnetic field lines get closer together hence indicating that the magnetic force is stronger here. The fields are closest together at the center of the magnet and farthest at the outside side of the magnet. </span></span>




8 0
3 years ago
Read 2 more answers
A 12.70 g bullet has a muzzle velocity (at the moment it leaves the end of a firearm) of 430 m/s when rifle with a weight of 25.
Norma-Jean [14]

Answer:

2.1844 m/s

Explanation:

The principle of conservation of momentum can be applied here.

when two objects interact, the total momentum remains the same  provided no external forces are acting.

Consider the whole system , gun and bullet. as an isolated system, so the net momentum is constant. In particular before firing the gun, the net momentum is zero. The conservation of momentum,

0=m_{bullet}*v_{bullet}  + m_{rifle}*v_{rifle}  \\

assume the bullet goes to right side and the gravitational acceleration =10 ms^{-2}

so now the weight of the rifle=\frac{25}{10}  

0=m_{bullet}*v_{bullet}  + m_{rifle}*v_{rifle}  \\\\0=(12.70*10^{-3}) *430ms^{-1} +(\frac{25}{10} )*v_{rifle} \\v_{rifle} =-2.1844ms^{-1}

this is a negative velocity to the right side. that means the rifle recoils to the left side

3 0
3 years ago
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