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2 years ago

What are some things that you do to make tasks like cleaning your room or doing the dishes more fun?

Physics

2 answers:

Genrish500 [490]2 years ago

8 0

Answer:

you canblisten to music that helps or you could set a reward that motivates u for example a candybar you could also get help feom a sibling that alway makes cleaning my room fun

Anna007 [38]2 years ago

5 0

Answer:

You can listen to music while doing either one, or you can get someone else to help you that way you have someone to talk to also you finish faster.

You might be interested in

The normal boiling point of cyclohexane is 81.0 oC. What is the vapor pressure of cyclohexane at 81.0 oC?

Aloiza [94]

Answer:

The vapor pressure of cyclohexane at 81.0°C is 101325 Pa.

Explanation:

Given that,

Boiling point = 81.0°C

Atmospheric pressure :

Atmospheric pressure is the force per unit area exerted by the weight of the atmosphere.

The value of atmospheric pressure is

$P=101325\ Pa$

Vapor pressure :

Vapor pressure is equal to the atmospheric pressure.

Hence, The vapor pressure of cyclohexane at 81.0°C is 101325 Pa.

6 0

3 years ago

As the distance between two objects decreases, the pull of gravity

aliya0001 [1]

Answer: increases

Explanation:

Because the relationship between hand d is counter

6 0

3 years ago

A solid box made from a material whose density is rhoS floats with two thirds of its volume submerged in a liquid whose density

jok3333 [9.3K]

Answer:

$\frac{\rho_S}{\rho_L} = \frac{2}{3}$

Explanation:

density of the solid box material = $\rho_s$

density of the liquid material = $\rho_L$

Given that

solid box floats with two thirds of its volume submerged in a liquid

let V be the volume of the box

then,

$V\rho_sg= \frac{2V}{3}\rho_L g$

⇒ $\frac{\rho_S}{\rho_L} = \frac{2}{3}$

so, the ratio of densities of solid and and the liquid is 2/3

7 0

3 years ago

A projectile is fired at an upward angle of 55° from the top of a 120 m cliff with a speed of 150 m/s. What will be its speed wh

telo118 [61]

Answer:

The speed when it strikes the ground below is V= 157.64 m/s < -56.92º .

Explanation:

V= 150m/s

α= 55º

hi= 120m

Vy= V*sinα

Vy= 122.87 m/s

Vx= V * cos α

Vx= 86.03 m/s

h= hi + Vy * t - g*t²/2

clearing t we get the total flying time of the projectile:

t(total fly)= 26.01 sec

0= Vy - g*t

clearing t we get the maximum height time:

t(max height)= 12.53 sec

to get the fall time:

t(fall)= t(total fly) - t(max height)

t(fall)= 13.48 sec

Vy'= g* t(fall)

Vy'= 132.1 m/s

V'= √(Vx² +Vy'²)

V'= 157.64 m/s

α'= tg⁻¹ (Vy'/Vx)

α'= -56.92º

7 0

2 years ago

Two lifeguards pull on ropes attached to a raft. If they pull in the same direction, the raft experiences a net external force o

makkiz [27]

$F_1=207.5\ N$

$F_2=92.5\ N$

Explanation:

Let $F_1\ and\ F_2$ is the two forces acting on the raft. If they pull in the same direction, the net force is given by :

$F_1+F_2=300$ ...............(1)

If they pull in opposite direction, net force is given by :

$F_1-F_2=115$ ...............(2)

It is required to find the magnitude of both forces. On solving equation (1) and (2) we get :

$F_1+F_2=300$

$F_1-F_2=115$

$F_1=207.5\ N$

$F_2=92.5\ N$

So, the forces are 207.5 N and 92.5 N. Hence, this is the required solution.

6 0

3 years ago