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3 years ago

Answer all of those questions and you will get the brainiest

Physics

2 answers:

zlopas [31]3 years ago

6 0

Answers:

1) A process that occurs when an object or a particle moves, referred to as kinetic energy

2) A potential energy is a stored amount of energy that changes depending on the relative positions.

3) Potential Energy is the energy stored in an object due to its position. Kinetic Energy is the energy of motion in a moving object.

a) C and B

b) A

c) From B to A or from C to A

d) From A to B or from A to C

evablogger [386]3 years ago

3 0

$\huge\mathfrak\green{answer}$

1) Kinetic energy of an object is the measure of the work an object can do by the virtue of its motion.

For Example : A river flowing at a certain speed comprises kinetic energy as water has certain velocity and mass.

2) Potential energy is the energy held by an object because of its position relative to other objects, stresses within itself, its electric charge, or other factors.

For Example : A child at the top of the slide

3) KINETIC ENERGY 

Kinetic energy is the kind of energy present in a body due to the property of its motion
It can be easily transferred from one body to another
It is relative with respect to nature
Flowing water is one of the examples of kinetic energy

POTENTIAL ENERGY 

Potential Energy is the type of energy present in a body due to the property of its state
It is not transferable
It is non-relative with respect to nature
Water present at the top of a hill is an example of potential energy

(make sure to draw a table and write them separately)

a) C and B

b) A

c) B to A then C to A

d) A to B then A to C

(mark me brainliest please I need 1 more :))

$\large\sf\green{thank \: you}$

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$\displaystyle |\vec{r}|=321.464\ km$

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The plane first flies 160 km at 66° east of north. To find the vector expression of this displacement, we must know the angle with respect to the East direction or North of East. Knowing the angle East of North is 66°, the required angle is 90°-66°=34°

The first vector is expressed as

$\displaystyle \vec{r_1}=\left \langle 160^o\ cos34^o, 160\ sin34^o \right \rangle$

$\displaystyle \vec{r_1}=\left \langle 132.646, 89.471 \right \rangle$

The second displacement is 260 km at 49° South of East. This angle is below the horizontal respect to the reference, thus we use -49°.

The second vector is expressed as:

$\displaystyle \vec{r_2}=\left \langle 260\ cos(-49^o), 260\ sin(-49^o)\right \rangle$

$\displaystyle \vec{r_2}=\left \langle 170.575,-196.224\right \rangle$

The total displacement is computed as the vectorial sum of both vectors

$\displaystyle \vec{r}=\vec{r_1}+\vec{r_2}=\left \langle 132.646+170.575\right \rangle+ \left \langle89.471-196.224\right \rangle$

$\displaystyle \vec{r}=\left \langle 303.221,-106.753\right \rangle\ km$

The magnitude of the total displacement is

$\displaystyle |\vec{r}|=\sqrt{303.221^2+(-106,753)^2}$

$\displaystyle |\vec{r}|=321.464\ km$

And the direction is

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$\displaystyle \theta =-19.395^o$

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