Answer:
a
Since the integral has an infinite discontinuity, it is a Type 2 improper integral
b
Since the integral has an infinite interval of integration, it is a Type 1 improper integral
c
Since the integral has an infinite interval of integration, it is a Type 1 improper integral
d
Since the integral has an infinite discontinuity, it is a Type 2 improper integral
Step-by-step explanation:
Considering a
Looking at this we that at x = 3 this integral will be infinitely discontinuous
Considering b
Looking at this integral we see that the interval is between 
which means that the integral has an infinite interval of integration , hence it is a Type 1 improper integral
Considering c
Looking at this integral we see that the interval is between 
which means that the integral has an infinite interval of integration , hence it is a Type 1 improper integral
Considering d
Looking at the integral we see that at x = 0 cot (0) will be infinity hence the integral has an infinite discontinuity , so it is a Type 2 improper integral
The numbers are 6 and -2.
6 + -2 is 4
as well as 6 x -2 is -12
9514 1404 393
Answer:
64r -48r -144
Step-by-step explanation:
The January cost expression is ...
62p -48p -144 -432 = profit
The cost is identified as having 3 components, so the profit will have 4 components:
(selling price)×p - ((cost per unit)×p +(fixed monthly cost)) -(first month startup cost) = profit
Comparing this to the given equation, we identify the components as ...
selling price = 62
cost per unit = 48
fixed monthly cost = 144
first month startup cost = 432
We note that 432 = 3×144, so is consistent with the description of startup costs.
Increasing the selling price by $2 will raise it from 62 to 64. In February, the initial month startup cost disappears, so the profit equation becomes ...
(selling price)×r - ((cost per unit)×r +(fixed monthly cost)) = profit
64r -48r -144 = profit
20 I think!
Look it up just to be sure
The answer to this question is going to be negative 6
