Answer:
1 - C
2 - A
3 - D
4 - B
Step-by-step explanation:
Consider an arbitrary function y=f(x).
1. f(x)>0 means y>0. y>0 determines all points on the graph which have positive y-coordinates. Positive y are corresponding to those x from the domain, for which graph lies above the x-axis. So 1 - C
2. f(x)<0 means y<0. y<0 determines all points on the graph which have negative y-coordinates. Negative y are corresponding to those x from the domain, for which graph lies below the x-axis. So 2 - A
3. To find y-intercept, we have to substitute x=0, so input is zero. Hence, 3 - D
4. To find x-intercept, we have to substitute y=0, so output is 0. Hence, 4 - B
Draw a diagram to illustrate the problem as shown below.
Each ball has mass = m.
The initial velocity of the blue ball = u.
The initial velocity of the red ball = 0.
Initial total momentum is
P1 = m*u + m*0 = mu
Final momentum is
P2 = mv + 3mv = 4mv
Because momentum is conserved,
mu = 4mv
u = 4v
Answer:
The velocity of the blue ball before the collision is 4v.
Angles 1 and 2 are a.) supplementary. This means that b.) the measure of each when added will be equal to 180 degrees. We can see this because they are both "flat" on a line next to each other.
A,B,C,D,E i THINK so because if you are 6 units away then the cordinets have to have six in it im not sure tho if X axis than A,B,C