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3 years ago

How many grams of carbon are in 36.6 grams in glucose

Chemistry

1 answer:

Lana71 [14]3 years ago

8 0

Answer:

14.64 grams of carbon

Explanation:

The Molecular formula of Glucose is C₆H₁₂O₆.

From the molecular formula, the Molar mass of Glucose is,

Mass of Carbon in Glucose = 6*12 = 72.

Mass of Hydrogen in Glucose = 12*1 = 12.

Mass of Oxygen in Glucose = 6*16 = 96.

Molar mass of Glucose = 72+12+96 = 180 grams.

180 grams of Glucose contains 72 grams of Carbon.

How many grams of Carbon are there in 36.6 grams of Glucose.

180 --> 72

36.6 --> ?

Let it be 'x' grams

Then, by Criss Cross, (x)(180) = (36.6)(72) => x = 14.64 grams.

Therefore 14.64 grams of carbon are there in 36.6 grams in glucose.

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A molecule is known to have a molar absorptivity of 18,650 at a certain wavelength. A spectrometer is tuned to this wavelength a

iren2701 [21]

Answer:

17,932.69 g/mol is the molecular weight of the substance.

Explanation:

Using Beer-Lambert's law :

Formula used :

$A=\epsilon \times c\times l$

where,

A = absorbance of solution = 1.04

c = concentration of solution =?

l = length of the cell = 1 cm

$\epsilon$ = molar absorptivity of this solution = 18,650 $M^{-1} cm^{-1}$

Now put all the given values in the above formula, we get the molar absorptivity of this solution.

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$Concentration=\frac{\text{Mass of compound}}{\text{Molecular mass of compound}\times V}$

V = Volume of the solution in L

Molecular weight of the substance = x

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Mass of the substance = 100 mg = 0.1 g

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6 0

3 years ago

Write the name of the product formed in the following synthesis reaction. potassium + fluorine

balandron [24]

Answer:

potassium and fluorine both react and form potassium fluoride.

Explanation:

Synthesis reaction:

It is the reaction in which two or more simple substance react to give one or more complex product.

General reaction:

A + B → AB

For example in given potassium and fluorine reaction both react and form potassium fluoride.

Chemical reaction:

K + F₂ → KF

Balanced chemical reaction:

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3 years ago

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Delicious77 [7]

Answer:

For a: The edge length of the crystal is 533.5 pm

For b: The atomic radius of potassium is 231.01 pm

Explanation:

For a:

To calculate the lattice parameter or edge length of the crystal, we use the equation:

$\rho=\frac{Z\times M}{N_{A}\times a^{3}}$

where,

$\rho$ = density = $0.855g/cm^3$

Z = number of atom in unit cell = 2 (BCC)

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$N_{A}$ = Avogadro's number = $6.022\times 10^{23}$

a = edge length of unit cell = ?

Putting values in above equation, we get:

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Conversion factor: $1cm=10^{10}pm$

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For b:

To calculate the edge length, we use the relation between the radius and edge length for BCC lattice:

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where,

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Putting values in above equation, we get:

$R=\frac{\sqrt{3}\times 533.5}{4}=231.01pm$

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