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PtichkaEL [24]
3 years ago
5

How many grams of carbon are in 36.6 grams in glucose

Chemistry
1 answer:
Lana71 [14]3 years ago
8 0

Answer:

14.64 grams of carbon

Explanation:

The Molecular formula of Glucose is C₆H₁₂O₆.

From the molecular formula, the Molar mass of Glucose is,

Mass of Carbon in Glucose = 6*12 = 72.

Mass of Hydrogen in Glucose = 12*1 = 12.

Mass of Oxygen in Glucose = 6*16 = 96.

Molar mass of Glucose = 72+12+96 = 180 grams.

180 grams of Glucose contains 72 grams of Carbon.

How many grams of Carbon are there in 36.6 grams of Glucose.

180 --> 72

36.6 --> ?

Let it be 'x' grams

Then, by Criss Cross, (x)(180) = (36.6)(72) => x = 14.64 grams.

Therefore 14.64 grams of carbon are there in 36.6 grams in glucose.

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Answer:

I believe it may be-

1. Series

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3. Parallel

4. Series

Explanation:

In a series circuit, electricity only has one path to follow while a parallel circuit has more than one path to follow.

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What are three units you can measure moler mass in
liraira [26]

By looking at a periodic table, we can conclude that the molar mass of lithium is 6.94g, the molar mass of zinc is 65.38g, and the molar mass of gold is 196.97g. Each of these quantities contains 6.02×1023 atoms of that particular element. The units for molar mass are grams per mole, or g/mol.

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What is formed when hydrobromic acid, hbr, and calcium hydroxide, ca(oh)2, are combined?
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The salt that is formed will be calcium bromide (calcium is located in group 2 so calcium bromide has a formula of CaBr2) 

so essentially we got:

HBr + Ca(OH)2 ------> CaBr2 + H2O </span>

balancing the elements: <span>

<span>2HBr(aq) + Ca(OH)2(aq) --------> CaBr2(aq) + 2H2O(l)</span></span>

6 0
3 years ago
Plesse help asap!!!​
Naily [24]

Answer:

4.4×10² cm³

Explanation:

From the question given above, the following data were obtained:

Diameter (d) = 68.3 mm

Height (h) = 0.120 m

Volume (V) =?

Next, we shall convert the diameter (i.e 68.3 mm) to cm.

This can be obtained as follow:

10 mm = 1 cm

Therefore

68.3 mm = 68.3 mm / 10 mm × 1 cm

68.3 mm = 6.83 cm

Therefore, the diameter 68.3 mm is equivalent 6.83 cm.

Next, we shall convert the height (i.e 0.120 m) to cm. This can be obtained as follow:

1 m = 100 cm

Therefore,

0.120 m = 0.120 m/ 1 m × 100 cm

0.120 m = 12 cm

Therefore, the height 0.120 m is equivalent 12 cm.

Next, we shall determine the radius of the cylinder. This can be obtained as follow:

Radius (r) is simply half of a diameter i.e

Radius (r) = Diameter (d) /2

r = d/2

Diameter (d) = 6.83 cm

Radius (r) =?

r = d/2

r = 6.83/2

r = 3.415 cm

Finally, we shall determine the volume of the cylinder as follow:

Radius (r) = 3.415 cm

Height (h) = 12 cm

Volume (V) =?

Pi (π) = 3.14

V = πr²h

V = 3.14 × (3.415) ² × 12

V = 440 cm³

V = 4.4×10² cm³

Therefore, the volume of the cylinder is 4.4×10² cm³

8 0
3 years ago
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