Question

how many carbon dioxide molecules are produced if 8.45 x 1023 of water molecules of water are produced

Answer 1

The given question is incomplete. The complete question is:

Determine how many carbon dioxide molecules are produced if molecules of water are produced

$C_2H_6(g)+O_2 (g)\rightarrow CO2(g)+H_2O(g)$

Answer: $5.60\times 10^{23}$ molecules of carbon dioxide are produced

Explanation:

The balanced chemical equation is:

$2C_2H_6(g)+7O_2 (g)\rightarrow 4CO2(g)+6H_2O(g)$

$\text{Moles of water}=\frac{\text{given molecules}}{\text{Avogadros number}}=\frac{8.45\times 10^{23}}{6.023\\times 10^{23}}=1.40moles$

Accoding to stoichiometry:

6 moles of water are produced along with = 4 moles of carbon dioxide

Thus 1.40 moles of water are produced along with = $\frac{4}{6}\times 1.40=0.93$ moles of carbon dioxide

Molecules of carbon dioxide = $moles\times {\text {Avogadros number}}=0.93\times 6.023\times 10^{23}=5.60\times 10^{23}$