The bond dissociation energy of the Cl - Cl bond is -958 kJ mol^-1.
<h3>What is the dissociation enthalpy?</h3>
Given that;
H-H bond energy = 435 kJ mol^-1
H-Cl bond energy = 431 kJ mol^-1
ΔHfO of HCL(g) = -92kJ mol^-1
Bond dissociation enthalpy of the Cl-Cl bond = x
-92 = 435 + 431 + x
x = -92 - (435 + 431)
x = -958 kJ mol^-1
Learn More about dissociation enthalpy:brainly.com/question/9998007?
#SPJ1
Answer:
38.75 L
Explanation:
From the question,
Applying Boyles Law,
PV = P'V'....................... Equation 1
Where P = Original pressure of the Argon gas, V = Original Volume of Argon gas, P' = Final pressure of Argon gas, V' = Final Volume of Argon gas.
make V the subject of the equation
V = P'V'/P.................... Equation 2
Given: P = 34.6 atm, V' = 456 L, P' = 2.94 atm.
Substitute these values into equation 2
V = (456×2.94)/34.6
V = 38.75 L
Answer: (A) It appears as a reactant in the net chemical reaction
Explanation:
A catalyst is A substance that speed up the chemical reaction without its self being consumed in the reactants or the products.It does this by lowering the activation energy of the reaction by speeding up the rate of reaction.
A.) In the beginning the universe was too hot for atoms to exist.
Because choice b,c,and d are all part of the big bang theory.
<h3><u>Answer;</u></h3>
B: The volume of hydrogen produced would be the same.
<h3><u>Explanation;</u></h3>
Ca(s) + 2 H2O(l) → Ca(OH)2(aq) + H2 (g)
- From the reaction;<u><em> the mole ratio of calcium to water is 1 : 2; which means 1 mole of calcium requires 2 moles of water to produce 1 mole of hydrogen gas. </em></u>
- Therefore; <em><u>changing the mass of water used will not affect the amount of hydrogen gas produced since the amount of hydrogen gas produced depends on the amount of calcium used. In this case, water is in excess, because 0.1 moles of calcium requires only 0.2 moles of water which is 3.6 g.</u></em>
- Hence; <em>since the amount of calcium remains the same the amount of hydrogen gas produced will remain the same.</em>
