What fraction is equivalent to 5/10 and has a denominator of 100
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Let x% be the salt concentration of first solution.
Then in 8ml, amount of salt =
Given that to this 8ml solution, 11ml solution of a 47% salt solution is mixed.
amount of salt in 11ml of 47% salt solution is =
So, total amount of salt in new mixture =
But given that this new solution is a 43% salt solution.
Hence amount of salt in new mixture of (8+11)=19ml solution of 43% salt solution is
Hence
8x+517 = 817
8x=817-517 = 300
x= 300/8 = 37.5
Hence the salt concentration in the first solution is 37.5%