Answer:
a) The graph shifted to the left by 3 units and up 1 unit.
b) Domain = x ∈ R Range = y ∈ R
(Domain (x) = All real numbers Range (y) = All real numbers)
c) (-4, 0)
d) (0, 2.442)
~Hope this helps! If you have any questions, please let me know!~
The class is weighted as follows:
60% Regular Tests
10% Final Exam
15% Project
15% Homework
The total weighted points possible for the class are as follows:
(100+100+100+100+100)*.6 + 100*.1 + 100*.15 + 100*.15 = 340
To calculate her individual final weighted grade we plug in her scores for each category and complete the following computation:
(92+83+77+84+82)*.6 + 88*.1 + 95*.15 + 77*.15 = 285.4
So her weighted grade percent would be 285.4/340 = 83.9% which is a B.
9514 1404 393
Answer:
2√30 ∠-120°
Step-by-step explanation:
The modulus is ...
√((-√30)² +(-3√10)²) = √(30 +90) = √120 = 2√30
The argument is ...
arctan(-3√10/-√30) = arctan(√3) = -120° . . . . a 3rd-quadrant angle
The polar form of the number can be written as ...
(2√30)∠-120°
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<em>Additional comments</em>
Any of a number of other formats can be used, including ...
(2√30)cis(-120°)
(2√30; -120°)
(2√30; -2π/3)
2√30·e^(i4π/3)
Of course, the angle -120° (-2π/3 radians) is the same as 240° (4π/3 radians).
__
At least one app I use differentiates between (x, y) and (r; θ) by the use of a semicolon to separate the modulus and argument of polar form coordinates. I find that useful, as a pair of numbers (10.95, 4.19) by itself does not convey the fact that it represents polar coordinates. As you may have guessed, my personal preference is for the notation 10.95∠4.19. (The lack of a ° symbol indicates the angle is in radians.)
Answer:
C
Step-by-step explanation:
Line of symmetry
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