3x × 40+ x × 70 = 285
120x + 70x = 285
190x = 285
x = 285/190
x = 1.5
Theodory traveled at the interstate for 1.5 hours
1-3 are about trigonometric ratios (SOH CAH TOA). 4, 5 are about the Law of Cosines, and 6 uses the Law of Sines.
1. Sin = Opposite/Hypotenuse
x = 10*sin(40°) ≈ 6.428
2. Sin = Opposite/Hypotenuse
x = arcsin(7/12) ≈ 35.69°
3. Tan = Opposite/Adjacent
x = 18/tan(52°) ≈ 14.063
4. b^2 = a^2 +c^2 -2ac*cos(B)
B = arccos((a^2 +c^2 -b^2)/(2ac)) = arccos((7^2 +13^2 -8^2)/(2*7*13))
B = arccos(11/13) ≈32.20°
5. Same formula.
x = √(a^2 +c^2 -2ab*cos(B)) = √(157-132cos(42°)) ≈ 7.675
6. The ratio of side lengths is the same as the ratio of the sines of the opposite angles.
6/10 = sin(x)/sin(100°)
x = arcsin((6/10)*sin(100°)) ≈ 36.22°
Answer:
x
=
e
y
+
3
−
4
Step-by-step explanation:
Algebra Examples
Popular Problems Algebra Find the Inverse y=e^(x+3)-4
y
=
e
x
+
3
−
4
Interchange the variables.
x
=
e
y
+
3
−
4
Solve for
y
.
Tap for fewer steps...
Since
y
is on the right side of the equation, switch the sides so it is on the left side of the equation.
e
y
+
3
−
4
=
x
Add
4
to both sides of the equation.
e
y
+
3
=
x
+
4
Take the natural logarithm of both sides of the equation to remove the variable from the exponent.
ln
(
e
y
+
3
)
=
ln
(
x
+
4
)
Use logarithm rules to move
y
+
3
out of the exponent.
(
y
+
3
)
ln
(
e
)
=
ln
(
x
+
4
)
The natural logarithm of
e
is
1
.
(
y
+
3
)
⋅
1
=
ln
(
x
+
4
)
Multiply
y
+
3
by
1
.
y
+
3
=
ln
(
x
+
4
)
Subtract
3
from both sides of the equation.
Answer:im not sure what u mean
Step-by-step explanation: