1.
where in a population:
p - the frequency of the <em>A</em> allele
q - the frequency of the <em>a</em> allele
- the frequency of the <em>AA</em> homozygous genotype
- the frequency of the <em>aa</em> homozygous genotype
2pq - the frequency of the <em>Aa</em> heterozygous genotype
A population at equilibrium will have the sum of all the alleles at the locus equal to 1.
2. Conditions:
A. The breeding population must be large
B. No natural selection
C. The mating must occur randomly
D. No mutations to cause changes in allelic frequency.
E. No changes in allelic frequency due to immigration or emigration.
3. By comparing the actual genetic structure of a population with what we would expect from a Hardy-Weinberg equilibrium, we can determine how much it deviates from the baseline provided by the mathematical model. Depending on how large the deviation is, one or more of the model's assumptions are being violated. Thus, we can attempt to determine which one.
Answer:
DNA → TACCATGGAATTACT
RNA → AUGGUACCUUAAUGA
PROTEIN → Methionine-Valine-Proline-Stop codon-Stop codon (AUG GUA CCU UAA UGA)
Explanation:
In nucleic acids (i.e., DNA and RNA), base complementarity refers to the interaction between antiparallel strands. In the double helix DNA molecule, adenine always interacts with thymine (uracil in RNA), while cytosine always interacts with guanine. Moreover, amino acids are encoded by codons, i.e., triplets of nucleotides in the messenger RNA (mRNA). Finally, stop codons are triplets of mRNA nucleotides (e.g., UAG, UAA, UGA) that indicates the end of the protein-coding sequence.
It’s to get all your different bones the right nutrients they need so they do get weak.