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mote1985 [20]
3 years ago
12

Can someone help me please​

Mathematics
2 answers:
IgorLugansk [536]3 years ago
7 0

Answer:

\sf   \dfrac{{x}^{a \: (b - c)} }{ {x}^{b \: (a - c)} } \:  \div  \:  \bigg \lgroup   \dfrac{ {x}^{b} }{ {x}^{a} } \bigg \rgroup^{c}  \:  =  \: 1

\\

Now,

\sf   \dfrac{{x}^{ab \:  -  \: ac} }{ {x}^{ba \:  - \: b c} } \:  \div  \:  \bigg \lgroup   \dfrac{ ({x}^{b} )}{( {x}^{a}) } \bigg \rgroup^{c}  \:  =  \: 1

\\

\sf   \dfrac{{x}^{ab \:  -  \: ac} }{ {x}^{ba \:  - \: b c} } \:  \div  \:   \dfrac{ {x}^{bc} }{{x}^{ac} } \:  =  \: 1

\\

We know that, When sign change from division to multiplication we should do reciprocal of next number.

Therefore we get,

\sf   \dfrac{{x}^{ab \:  -  \: ac} }{ {x}^{ba \:  - \: b c} } \:   \times \:   \dfrac{ {x}^{ac} }{{x}^{bc} } \:  =  \: 1

\\

\sf   \dfrac{{x}^{ab \:  -  \:  \cancel {ac }\:  +  \:  \cancel{ac}} }{ {x}^{ba \:  - \: \cancel{ b c} \:  +  \:  \cancel{bc}} }  \:  =  \: 1

\\

\sf   \dfrac{{x} \:  ^{ \cancel{ab}} }{ {x} \: ^{\cancel{ba}} }  \:  =  \: 1

\\

\bigstar \: \:   \underline{ \boxed{\sf   x  \:  =  \: 1}} \: \:  \bigstar

\\

\huge\bf \dag \:   \gray{RHS = LHS} \:  \dag

\\

\large \star \:  \tt Hence, Verified  \: \star

ANEK [815]3 years ago
5 0

Step-by-step explanation:

kindly see attached picture

hope it helped you:)

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A number is :

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And we're done.

Thanks for watching buddy good luck.

♥️♥️♥️♥️♥️

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